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docker41 [41]
3 years ago
8

The college athletic director recorded the highest noise levels reached during 7 sporting events. The highs were:

Mathematics
1 answer:
sergiy2304 [10]3 years ago
8 0

Answer:

90

Step-by-step explanation:

Mean:

(88 + 88 + 88 + 87 + 84 + 97 + 95)/7

627/7

89.57

90

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The proof that AMNS AQNS is shown.
FrozenT [24]

Answer:

The answer is "MS and QS".

Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e   MS=SQ

In ΔMNS and ΔQNS

MN=QN       (∵ MNQ is isosceles triangle)

∠NMS=∠NQS     (∵ MNQ is isosceles triangle)

MS=SQ         (Given)

By SAS rule, ΔMNS ≅ ΔQNS.

Hence, segments MS and SQ are therefore congruent by the definition of bisector.

The correct option is MS and QS

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3 years ago
Who want to talk b o r e d
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Step-by-step explanation:

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3 years ago
What is the decimal equivalent of 9 1/2%
V125BC [204]

Answer:

Step-by-step explanation:

9.5

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If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc
grin007 [14]

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)\\(16)^2=90+2(ab+bc+ca)\\256-90=2(ab+bc+ca)\\166/2=ab+bc+ca\\83=ab+bc+ca\\a^3-b^3-c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))\\16(90-(83))\\16(7)\\=112

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3 years ago
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