B. 245 million
from the end of Carboniferous Period to the beginning of the Triassic period
Answer:
article 2
Explanation:
Article Two of the United States Constitution establishes the executive branch of the federal government, which carries out and enforces federal laws.
The answer is 0.47 or 47%.
Let's first distinguish some terms and their frequencies.
R - the dominant allele that causes red eyes
r - the recessive allele that causes green eyes
Since R is dominant over r, lizards with at least one dominant R allele will have red eyes. Therefore, the genotypes and the phenotypes are as following:
genotypes - phenotypes
RR - the lizards with red eyes
Rr - the lizards with red eyes
rr - the lizards with green eyes
Now, we will use some Hardy-Weinberg equations:
p + q = 1
p² + 2pq + q² = 1
where:
p - the frequency of dominant allele R
q - the frequency of recessive allele r
p² - the frequency of lizards with genotype RR
2pq - the frequency of lizards with genotype Rr
q² - the frequency of lizards with genotype <span>rr
</span>
We are interested in <span>the frequency p of the dominant R allele.
</span>So, we have the frequency (72%) of the lizards that have red eyes. However, lizards with genotypes RR and Rr will have red eyes. Since their frequencies are p² and 2pq, respectively, we have:
p² and 2pq = 72% = 72/100 = 0.72
Now, use this in the equation p² + 2pq + q² = 1:
0.72 + q² = 1
q² = 1 - 0.72 = 0.28
From here, we will calculate q and later p using the formula p + q = 1:
q² = 0.28
q = √0.28 = 0.53
p + q = 1
p + 0.53 = 1
p = 1 - 0.53
p = 0.47
Answer:
8.800s
Explanation:
When the performer swings, she oscillates in SHM about Lo of the string with time period To = 8.90s.
First, determine the original length Lo, where for a SHM the time period is related to length and the gravitational acceleration by the equation
T = 2π×√(Lo/g)..... (1)
Let's make Lo the subject of the formulae
Lo = gTo^2/4π^2 ..... (2)
Let's put our values into equation (2) to get Lo
Lo = gTo^2/4π^2
= (9.8m/s^2)(8.90s)^2
------------------------------
4π^2
= 19.663m
Second instant, when she rise by 44.0cm, so the length Lo will be reduced by 44.0cm and the final length will be
L = Lo - (0.44m)
= 19.663m - 0.44m
= 19.223m
Now let use the value of L into equation (1) to get the period T after raising
T = 2π×√(L/g)
= 2π×√(19.223m/9.8m/s^2)
= 8.800s
DNA?? And I hope you have a good day too x
