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Kisachek [45]
3 years ago
12

Which expression is equivalent to -6(3x-2/3)?​

Mathematics
2 answers:
nlexa [21]3 years ago
6 0

D

i got it right on the unit test review

kupik [55]3 years ago
3 0
The answer is D -18x+4
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13 ≤ 4n n = 3 <br><br> True or false ? ( show work )
yaroslaw [1]

Answer:

False

Step-by-step explanation:

13 ≤ 4n if n = 3

13 ≤ 12

Is this true?

First of all this symbol (≤) means

  1. Less than
  2. Equal to

Is 13 less than 12?

No

Is 13 equal to 12?

No

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5 0
3 years ago
3c+6=18 how do you work this problem?
Bogdan [553]

Answer:

c = 4

Step-by-step explanation:

Simplifying

3c + 6 = 18

Reorder the terms:

6 + 3c = 18

Solving

6 + 3c = 18

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6' to each side of the equation.

6 + -6 + 3c = 18 + -6

Combine like terms: 6 + -6 = 0

0 + 3c = 18 + -6

3c = 18 + -6

Combine like terms: 18 + -6 = 12

3c = 12

Divide each side by '3'.

c = 4

Simplifying

c = 4

4 0
3 years ago
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What is the measure of
Andreas93 [3]

Answer:

43

Step-by-step explanation:

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3 years ago
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Josie bought a new mirror. The mirror has 5 sides. What is the shape of the mirror?
yuradex [85]
If Josie bought a mirror with 5 sides it would be a pentagon
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3 years ago
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Polygon F has an area of 36 square units. Aimar drew a scaled version of Polygon F and labeled it Polygon G. Polygon G has an ar
Free_Kalibri [48]

Answer:

1/3

Step-by-step explanation:

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

Each side of Polygon FFF was multiplied by a certain value, known as the scale factor , to result in an area that is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

[Show me an example of how scale factor affects area]

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction

 

 

\begin{aligned} A &= \left(l\times\dfrac1{10}\right)\times\left(w\times\dfrac1{10}\right) \\ \\ A&= l\times w\times\dfrac1{10}\times\dfrac1{10} \\ \\ A&= lw \times \left(\dfrac1{10}\right)^2\end{aligned}  

 

 

 

 

 

 

 

 

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction\left(\dfrac1{10}\right)^2  

 

left parenthesis, start fraction, 1, divided by, 10, end fraction, right parenthesis, start superscript, 2, end superscript

Hint #22 / 3

The area of a polygon created with a scale factor of \dfrac1x  

x

1

​  start fraction, 1, divided by, x, end fraction has \left(\dfrac1{x}\right)^2(  

x

1

​  )  

2

left parenthesis, start fraction, 1, divided by, x, end fraction, right parenthesis, start superscript, 2, end superscript the area of the original polygon:

\left(\text{scale factor}\right)^2=\text{fraction of the area the scale copy has}(scale factor)  

2

=fraction of the area the scale copy hasleft parenthesis, s, c, a, l, e, space, f, a, c, t, o, r, right parenthesis, start superscript, 2, end superscript, equals, f, r, a, c, t, i, o, n, space, o, f, space, t, h, e, space, a, r, e, a, space, t, h, e, space, s, c, a, l, e, space, c, o, p, y, space, h, a, s

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF. Let's substitute \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction into the equation to find the scale factor.

\left(\dfrac1{?}\right)^2=\dfrac19(  

?

1

​  )  

2

=  

9

1

​  left parenthesis, start fraction, 1, divided by, question mark, end fraction, right parenthesis, start superscript, 2, end superscript, equals, start fraction, 1, divided by, 9, end fraction

The scale factor is \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction.

Hint #33 / 3

Aimar used a scale factor of \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction to go from Polygon FFF to Polygon GGG.

4 0
3 years ago
Read 2 more answers
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