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4 years ago

An item is regularly priced at $80. Juan bought It at a discount of 20% off the regular price. How much did Juan pay?

1 answer:

3 0

Hello there! So, the item has a 20% discount, but Juan still had to pay 80% for the item. To find the amount he paid, all you have to do is multiply the price by the percentage. We multiply by 80%, because he still had to pay the portion of the price. 80 * 80% (0.8) is 64. The. Juan paid $64.

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Is (0,0) a solution of the graphed inequality?

sweet [91]

No because it is not within the shaded area

5 0

3 years ago

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You have a shelf that holds 25 1/2 pounds. What is the most number of 1 1/4 pound books that the shelf can hold?

patriot [66]

Answer:

20 books

Step-by-step explanation:

given that the shelf can hold 25 1/2 lbs (i.e 25.5 lbs), and that each book weighs 1 1/4 ln (i.e 1.25 lbs)

number of books which the shelf can hold

= weight that the shelf can hold ÷ weight of each book

= 25.5 ÷ 1.25

= 20.4 books

because having 0.4 of a book (i.e part of a book) would not be very feasable, we have to round the number of books down to the nearest whole number)

20.4 books rounded down to nearest whole number = 20 books (answer)

5 0

3 years ago

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Choose the inequality shown by this diagram

Slav-nsk [51]

Answer:

C: -2<x≤7

Step-by-step explanation:

-2<x, as there is an open circle on -2
x≤7 as there is a closed circle on 7

Put them together, -2<x≤7

3 0

3 years ago

Joe bought 5 apples and 4 bananas for $6. Dawn bought 3 apples and 6 bananas for $6.30. How much foes each apple and each banana

zepelin [54]

Answer:

Apple = $0.6

Banana = $0.75

Step-by-step explanation:

Let us represent Apple by A and Banana by B

For Joe,

5A + 4B = 6 (1)

For Dawn

3A + 6B = 6.3 (2)

To eliminate A, Multiply equation (1) by 3 and equation (2) by 5

15A + 12B = 18 (3)

15A + 30B = 31.5 (4)

subtracting equation (4) from (3)

15A - 15A +12B - 30B = 18 - 31.5

-18B = -13.5

divide through by -18

-18B/-18 = -13.5/-18

B = 0.75

substitute 0.75 in equation (1)

5A + 4B = 6

5A + 4(0.75) = 6

5A + 3 = 6

subtract 3 from both sides

5A + 3 - 3 = 6 - 3

5A = 3

divide through by 5

5A/5 = 3/5

A = 0.6

4 0

3 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago