Answer:
y = 12
Step-by-step explanation:
∵ m∠ABC = 40
∵ BD ray is the bisector of ∠ABC
∴ m∠ABD = m∠CBD = 20
In 2 Δ BAD and BCD:
∵ m∠BAD = m∠BCD = 90°
∵ m∠ABD = m∠CBD = 20°
∵ BD is a common side in the two triangles
∴ ΔABD congruent to ΔCBD⇒(AAS)
∴ AD = CD
∴ 3y + 6 = 5y - 18
∴ 5y - 3y = 6 + 18
∴ 2y = 24
∴ y = 24/2 = 12
X + 14 = 12
x + 14 - 14 = 12 - 14
x = 12 - 14
Options B and C are related to the given equation.
Step-by-step explanation:
here
f(x)=x^2+6
Now
Replacing the value of x
f(3x)=3x^2 +6
What you do is you rearrange and simplify both equations to have them in terms of y, and then graph them. If it asked for a solution, their point of intersection would be the solution.
Answer:
Step-by-step explanation:
Distance Formula: 
Simply plug in your 2 coordinates into the distance formula to find distance <em>d</em>:
