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vredina [299]
3 years ago
13

A rational function can have infinitely many x-values at which it is not continuous. True or False. If false, explain

Mathematics
1 answer:
sattari [20]3 years ago
3 0
<span>It is false since the rational function is discontinuous when the denominator is zero. But the denominator is a polynomial and a polynomial has only finitely many zeros. So the discontinuity points of a rational function is finite. </span>
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The 5 - number summary of the distribution obtained from the boxplot is :

  • Minimum = 20
  • Maximum = 85
  • Lower quartile = 35
  • Median = 44
  • Upper quartile = 58
  • Outlier = 100

Firstly, we need to extract the values for the amount spent by females :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The five number summary include ;

  • Minimum, lower Quartile, Median, Upper Quartile and Maximum values.

Rearranging the data in ascending order :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The boxplot clearly and easily gives the five number summary of the distribution :

  • Minimum = 20 (starting point of the whisker)
  • Lower quartile = 35 (starting point of the box)
  • Median = 44 (vertical line in between the box)
  • Upper quartile = 58 (endpoint of the box)
  • Maximum = 85 (endpoint of the upper whisker).

Outlier :

  • Lower boundary = LOWER QUARTILE - (1.5 × IQR)
  • Upper boundary = UPPER QUARTILE + (1.5 × IQR)
  • IQR = UPPER QUARTILE - LOWER QUARTILE
  • IQR = (58 - 35) = 23

Lower boundary = 35 - (1.5 × 23) = 0.5

Upper boundary = 58 + (1.5 × 23) = 92.5

  • The point denoted by a dot on the boxplot is an outlier = 100

Hence, values lesser than 0.5 or greater than 92.5 are outliers.

Therefore, 100 is an outlier.

Learn more : brainly.com/question/24582786

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