Question

I need help with this geometry math assignment I been struggling and I need help on it very fast and it is due today so please help me out I will mark you Brainly and I’m stress and worry.Also please help me I need the answer I try my best

Answer 1

Answer:

12a. (-6, -6)

12b. 17

13a. y = $\frac{-1}{2}$ x + $\frac{3}{2}$

13b. 2

Step-by-step explanation:

12a. Using the midpoint formula:

$(\frac{-9-3}{2} ,\frac{2-14}{2} )$ = $(\frac{-12}{2} , \frac{-12}{2})$ = (-6, -6)

12b. Using the Distance formula:

d = $\sqrt{(3 - (-9))^{2} +( 14 - 2)^{2} }$ = $\sqrt{(12)^{2}+(12)^{2} }$ = $\sqrt{144 + 144}$ = $\sqrt{288}$

= 12$\sqrt{2}$ or 17

13a. x + 2y = 3

2y = 3 - x

y = $\frac{-1}{2}$ x + $\frac{3}{2}$

13b. The perpendicular slope is 2