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3 years ago

12

If the ball is orange , then the ball bounces .

1 answer:

Harman [31]3 years ago

3 0

What is the question and where is the answers

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8.) Out of 600 employees, only 270 are happy with their pay. What percent is this? (Please show your work.) *

Gnom [1K]

For this case we can raise a rule of three:

600 employees -------------> 100%

270 employees -------------> x

Where the variable "x" represents the percentage of employees who are satisfied with their salary. So, we have:

$x = \frac {270 * 100} {600}\\x = 45$

Thus, 45% of employees are satisfied with their salary.

Answer:

45%

5 0

4 years ago

Read 2 more answers

The frequency table shows the scores from rolling a dice.

ExtremeBDS [4]

Answer: 2

Step-by-step explanation:

The mode is the number that is shown the most.

3 0

3 years ago

If someone can help me with this I’d really appreciate it!! ( links = report )

zepelin [54]

It’s 4

The area of a rhombus is diagonal 1 x diagonal 2 / 2. Since we know the area is 120 and the diagonal 1 is 15 we would divide them and get 8. But then you would do divide 8 by 2 because of the last part of the formula for a rhombus and get 4.

Hope that helps!

8 0

3 years ago

Opposite of jumping down 10 steps<br>

nika2105 [10]

The opposite of jumping down 10 steps would be walking up 10 steps

6 0

3 years ago

Read 2 more answers

Choose the solution to this inequality. < 3 34 O A. y. -12 B. ys o o c. y< 1 / 3 O D. y> 4

Rasek [7]

Answer:

$\boxed{\boxed{\bf y < - \cfrac{1}{2}}}$

<u>Option A</u>

Step-by-step explanation:

$\bf \: Given \: inequality :$

$\sf \implies \: \cfrac{4}{3 } \: y < \cfrac{ - 8}{3} \: y$

We need to find the solution to the inequality.

$\bf \: Solution:$

$\sf \implies \: \cfrac{4}{3 } \: y < \cfrac{ - 8}{3} \: y$

$\rm \: Firstly,Flip \: the \: inequality :$

$\sf \implies \cfrac{ - 8}{3} y > \cfrac{4}{3}$

$\rm \: Then,\; multiply\; each\: side \: \: by \: \cfrac{ - 3}{8} \: :$

$\sf \implies \: \cfrac{ - 8}{3}y \times \cfrac{ 3}{ - 8} > \cfrac{4}{3} \times \cfrac{ 3}{ - 8}$

$\rm \: Use \: cancellation \: method \: to \: cancel \: LHS:-$

<u>Steps </u><u>of </u><u>cancelling :-</u>

<em>Cancel -8( which is on the numerator) and -8 (on the denominator) :</em>

$\sf \implies \cfrac{ \cancel{- 8}}{3}y \times \cfrac{ 3}{ \cancel{- 8} } > \cfrac{4}{3} \times \cfrac{ 3}{ - 8}$

<em>Cancel 3(which is on the numerator)</em><em> </em><em>and 3( which is on the denominator)</em><em> </em>:

$\sf \implies\cfrac{ \cancel{- 8}}{ \cancel3}y \times \cfrac{ \cancel 3}{ \cancel{- 8} } > \cfrac{4}{3} \times \cfrac{ 3}{ - 8}$

<em>Results to,</em>

$\sf \implies \: 1y < \cfrac{4}{3} \times \cfrac{3}{ - 8}$

<em>As we know 1y equals to y.</em><em> </em>So,

$\sf \implies \: y < \cfrac{4}{3} \times \cfrac{3}{ - 8}$

$\rm \: Now, Cancel \: the \: RHS :$

<u>Steps </u><u>of</u><u> cancelling:-</u>

<em>Cancel 3 (which is on the numerator) and cancel 3 (which is on the denominator)</em><em>:</em>

$\sf \implies \: y < \cfrac{4}{ \cancel3} \times \cfrac{ \cancel3}{ - 8}$

$\sf \implies{y} < 4 \times \cfrac{1}{ - 8}$

<em>Cancel 4 and -8 </em><em> </em><em>:</em>

$\sf \implies \: y < \cancel{4} \times \cfrac{1}{ \cancel{ - 8}}$

<em>Results to,</em>

$\sf \implies \: y < 1 × \cfrac{ - 1}{2}$

$\sf \implies \: y < \cfrac{ - 1}{2}$

$\rm \: Which \: can \: be \: rewritten \: as,$

$\sf \implies \: y < - \cfrac{1}{2}$

This matches with option A.

Hence, Option A is correct!

$\rule{225pt}{2pt}$

I hope this helps!

Let me know if you have any questions.I am joyous to help!

7 0

3 years ago