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Rom4ik [11]
3 years ago
7

If someone can help me with this I’d really appreciate it!! ( links = report )

Mathematics
1 answer:
zepelin [54]3 years ago
8 0
It’s 4

The area of a rhombus is diagonal 1 x diagonal 2 / 2. Since we know the area is 120 and the diagonal 1 is 15 we would divide them and get 8. But then you would do divide 8 by 2 because of the last part of the formula for a rhombus and get 4.

Hope that helps!
You might be interested in
141.1933-67.53 =<br> (Divided, not minus)
Sphinxa [80]

Answer: I think its 2.09

Step-by-step explanation:

But i'm not sure.

5 0
3 years ago
Tony runs to keep fit. He wants to run a total of 20 km each week. Here are the
IgorLugansk [536]

Answer:

Tony run 19.5 km last week, so he must have run 0.5 km more, to complete 20km run last week.

Step-by-step explanation:

Distance Tony ran last week are

6.25 km

4 km 750 m

872 km (<em>Note: This would be 8 </em>\frac{1}{2}<em> km and not 872 km</em>)

We will add all the distances to check if they sum up to 20km or not.

First we will convert 4 km 750 m into km

We know that 1000 m = 1 km

So, 1 m = 1/1000 km

750 m = 750/1000 = 0.75 km

Now 4km + 0.75 km = 4.75 km

So, 4 km 750 m = 4.75 km

and 8 \frac{1}{2} km = 8.5 km

Now, finding Distance covered by Tony during last week = 6.25 km + 4.75 km + 8.5 km

= 19.5 km

So, Tony run 19.5 km last week, so he must have run 0.5 km more, to complete 20km run last week.

8 0
3 years ago
A paper reported that in a representative sample of 282 American teens age 16 to 17, there were 71 who indicated that they had s
elena-s [515]

Answer:

z=\frac{0.252 -0.25}{\sqrt{\frac{0.25(1-0.25)}{282}}}=0.0776  

p_v =P(z>0.0776)=0.4691  

Since the p value is higher than the significance level so then we can conclude that we have enough evidence to FAIL to reject the null hypothesis and there is no evidence in order to say that the true proportion of teens more than a quarter of Americans age 16 to 17 have sent a text message while driving is higher than 0.25

Step-by-step explanation:

Information provided

n=282 represent the sample selected

X=71 represent the teens indicated that they had sent a text message while driving

\hat p=\frac{71}{282}=0.252 estimated proportion of teens indicated that they had sent a text message while driving

p_o=0.25 is the value that we want to test

\alpha=0.01 represent the significance level

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to check if more than a quarter of Americans age 16 to 17 have sent a text message while driving, and the hypothesis are:

Null hypothesis:p\leq 0.7  

Alternative hypothesis:p > 0.25  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.252 -0.25}{\sqrt{\frac{0.25(1-0.25)}{282}}}=0.0776  

Decision

The p value for this case is:

p_v =P(z>0.0776)=0.4691  

Since the p value is higher than the significance level so then we can conclude that we have enough evidence to FAIL to reject the null hypothesis and there is no evidence in order to say that the true proportion of teens more than a quarter of Americans age 16 to 17 have sent a text message while driving is higher than 0.25

8 0
4 years ago
HI PLEASE HELPZ I AM REALLY STRUGGLING
garri49 [273]
3x + (2x - 25) = 180
5x - 25 = 180
5x - 25 + 25 = 180 + 25
5x = 205
5x / 5 = 205 / 5
X = 41
Hope that is right, sorry if it’s not
Supplementary means it equals 180 degrees
5 0
3 years ago
Find the surface area:
Lubov Fominskaja [6]
.nshsheksdjjwksksdhsn
5 0
3 years ago
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