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VARVARA [1.3K]
3 years ago
6

Find the slope of the line that passes through the points (4, -1) and (4, 3).

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
5 0

Answer:

undefined

Step-by-step explanation:

use math way to solve great app to help finding slopes

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Solve 15 ≥ -3x or 2/5x ≥ -2. <br><br> A.) {x | x ≤ -5}<br> B.) {x | x ≥ -5}<br> C.) {all reals}
Lapatulllka [165]
15 \geq -3x\quad|:(-3)\qquad\vee\qquad  \dfrac{2}{5}x \geq -2\quad|\cdot5\\\\\\&#10;-5 \leq x\qquad\vee\qquad  2x \geq -10\quad|:2\\\\\\&#10;-5 \leq x\qquad\vee\qquad  x \geq -5\\\\\\x\geq -5\qquad\implies\qquad\boxed{\{x | x \geq -5\}}

Answer B.
6 0
3 years ago
Read 2 more answers
Can someone please help me?
Alisiya [41]

Answer:

Step-by-step explanation:

That'd be the Substitution Property.  Substitute -2 for x in x + 8 = 6 and arrive at the true statement 6 = 6.

4 0
3 years ago
Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'
AleksandrR [38]
Let's start by assuming Armando's house is between Joey's and the park. 

Let x be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park. 

</span>\dfrac{9}{10} = x + \dfrac{3}{5}

x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}

That's probably the answer they're looking for.  But what if the park is between Joey and Armando's houses or Joey is between the park and Armando?  (The latter isn't really possible with the given distances.)

Let a, b, c be the distances between three collinear points like we have here.  Our equation is really a few equations in one, something like

\pm a \pm b = \pm c

Let's get rid of the plus/minuses. Squaring,

a^2 + b^2\pm 2ab = c^2

\pm 2ab = c^2-a^2-b^2

4a^2b^2 = (c^2-a^2-b^2)^2

For us, that's a quadratic equation for c^2

4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2

I'll skip right to the solutions,

c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}


c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0
3 years ago
The price of a pair of jeans was $60 after a 50% markup. What was the price of the jeans before the markup?
zhenek [66]

Answer:

40

Step-by-step explanation:

We have an original price p

We mark them up by 50%

p + p*50%

Changing to decimal form

p+.50p = 1.5p

The new price is 60 dollars

1.5p = 60

Divide each side by 1.5

1.5p/1.5 = 60/1.5

p =40

The original price is 40

5 0
3 years ago
Read 2 more answers
Solve for x. <br><br> 3(x + 5) - 2(x + 2) = 20
IRINA_888 [86]
[tex] 3(x + 5) - 2(x + 2) = 20 \\
3x + 15 - 2x - 4 = 20\\
5x + 11 = 20\\
5x = 9\\
x = 1\frac{4}{5} [tex]
4 0
3 years ago
Read 2 more answers
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