All categories

3 years ago

Suppose you are driving 60 miles per hour. what is your rate of speed in miles per minute?

Mathematics

2 answers:

alexdok [17]3 years ago

8 0

60 miles per hour

⇒ 60 miles per 60 mins . <==== convert 1 hour to 60 mins

⇒ 1 miles per min <==== Find 1 min

Speed = 1 mile/min

Verdich [7]3 years ago

6 0

So if it is 60 miles per hour it is basically 60 miles per 60 minutes. $\frac{60}{60}$ when you simplify it, it is going to be 1/1=1 The answer is 1 mile per minute

You might be interested in

Having some trouble here need some help not really good at this

kolezko [41]

Answer:

none of these are correct

Step-by-step explanation:

4 0

2 years ago

What is the sum of the geometric sequence 4, 16, 64, ƒ if there are 8 terms?

pogonyaev

In a Geometric Sequence, each term is found by multiplying the previous term by a constant. For this case, the constant is 4. To find the sum of the geometric sequence with 8 terms, we use the formula as follows:

∑(ar^k) = a ( 1-r^n) / (1-r)

where a is the first term, r is the constant, n is the number of terms

∑(ar^k) = 4 ( 1-4^8) / (1-4)
∑(ar^k) = 87380

7 0

3 years ago

For their wedding reception, Jamie and Noah spent a total of $1845 on food and drinks. If the caterer charged them $10.25 per pe

Mumz [18]

They invited 180 people.
1845 divided by 10.25 equals 180

4 0

3 years ago

Read 2 more answers

The right arrow symbol used to show the transition from a point to its image after a transformation is not contained within the

Naily [24]

Dmdkdjkdjddjjfjjtjjtjfhfjtjt

4 0

3 years ago

A researcher wishes to determine whether people with high blood pressure can lower their blood pressure by performing yoga exerc

Anastaziya [24]

Answer:

90% confidence interval for the difference between the two population means

( -23.4166 , -6.5834)

Step-by-step explanation:

Step(i):-

Given first sample size n₁ = 100

Given mean of the first sample x₁⁻ = 178

Standard deviation of the sample S₁ = 35

Given second sample size n₂= 100

Given mean of the second sample x₂⁻ = 193

Standard deviation of the sample S₂ = 37

Step(ii):-

Standard error of two population means

$se(x^{-} _{1} -x^{-} _{2} ) = \sqrt{\frac{s^{2} _{1} }{n_{1} }+\frac{s^{2} _{2} }{n_{2} } }$

$se(x^{-} _{1} -x^{-} _{2} ) = \sqrt{\frac{(35)^{2} }{100 }+\frac{(37)^{2} }{100 } }$

$se(x^{-} _{1} -x^{-} _{2} ) = 5.093$

Degrees of freedom

ν = n₁ +n₂ -2 = 100 +100 -2 = 198

t₀.₁₀ = 1.6526

Step(iii):-

90% confidence interval for the difference between the two population means

$(x^{-} _{1} - x^{-} _{2} - t_{\frac{\alpha }{2} } Se (x^{-} _{1} - x^{-} _{2}) , x^{-} _{1} - x^{-} _{2} + t_{\frac{\alpha }{2} } Se (x^{-} _{1} - x^{-} _{2})$

(178-193 - 1.6526 (5.093) , 178-193 + 1.6526 (5.093)

(-15-8.4166 , -15 + 8.4166)

( -23.4166 , -6.5834)

4 0

3 years ago