The object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
<h3>What is the distance?</h3>
Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.
It is given that:
An object is traveling at a steady speed of 10 1/5 mi/h.
u = 10 1/5 min/h
u = 51/5 min/h
As we know, the speed-distance relationship:
time = distance/speed
distance = 1 4/5 = 9/5
time = (9/5)/(51/5)
time = 9/51 hours
time = (9/51)60
time = 10.58 minutes
Thus, the object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
Learn more about the distance here:
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Answer:
-2x² - 16x + 4
Step-by-step explanation:
Step 1: Write out expression
6x² - 9x + 3 - (8x² + 7x - 1)
Step 2: Distribute negative
6x² - 9x + 3 - 8x² - 7x + 1
Step 3: Combine like terms (x²)
-2x² - 9x + 3 - 7x + 1
Step 4: Combine like terms (x)
-2x² - 16x + 3 + 1
Step 5: Combine like terms (constants)
-2x² - 16x + 4
Answer:
x = 6
Step-by-step explanation:
Given:
log₆(x) = 1
Now,
From the properties of log
logₓ (z)= 
(where the base of the log is equal for both numerator and the denominator)
also,
log(xⁿ) = n × log(x)
thus,
using the above properties, we can deduce the results as:
logₓ(y) = n is equivalent to y = xⁿ
therefore,
the given equation can be deduced as:
log₆(x) = 1
into,
x = 6¹
or
x = 6
