PLEASE ANSWER QUICK: How do you find the distance between two points on a number line when the units are variables.

Mathematics

2 answers:

svetlana [45]3 years ago

8 0

PLEASE ANSWER QUICK: How do you find the distance between two points on a number line when the units are variables.

9966 [12]3 years ago

6 0

If we want to find the distance between two points on a number line use the distance formula:

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Solve for x. -6 > 10 - 8.0 Enter your answer as an inequality in the box. Plz help I will mark as branliest if right

Neporo4naja [7]

Answer:

2>x

Step-by-step explanation:

-6>10 - 8x.

Simplify it to get

-16>-8x

Simplify it again to get rid of the negatives. (Divide everything by -1)

16>8x

Simplify again

2>x

8 0

3 years ago

Find the following Euler Totients using Euler’s Theorem, as explained on p.409 of the text (10 points each): a.ϕ(13) b.ϕ(81) c.ϕ

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(a) $\varphi(13)=12$ since 13 is prime.

(b) $81=3^4$ , and there are 81/3 = 27 multiples of 3 between 1 and 81, which leaves 81 - 27 = 54 numbers between 1 and 81 that are coprime to 81, so $\varphi(81)=54$ .

(c) $100=2^2\cdot5^2$ ; there are 50 multiples of 2, and 20 multiples of 5, between 1 and 100; 10 of these are counted twice (the multiples of 2*5=10), so a total of 50 + 20 - 10 = 60 distinct numbers not coprime to 100, leaving us with $\varphi(100)=100-60=40$ .

(d) $102=2\cdot3\cdot17$ ; there are 51 multiples of 2, 34 multiples of 3, and 6 multiples of 17, between 1 and 102. Among these, we double-count 17 multiples of 2*3=6, 3 multiples of 2*17=34, and 2 multiples of 3*17=51; we also triple-count 1 number, 2*3*17=102. There are then 51 + 34 + 6 - (17 + 3 + 2) + 1 = 70 numbers between 1 and 102 that are not coprime to 102, and so $\varphi(102)=102-70=32$ .