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algol [13]
3 years ago
7

PLEASEE HELP!! What is the value of x? Enter your answer in the box

Mathematics
1 answer:
madreJ [45]3 years ago
3 0
First we need to figure out how long YK is and the best way to do this is to set up a proportion

34         x
----- = ------
95.2      168

then cross multiply and divide

34 times 168=5712/95.2=60

then add the two parts of the line

60+34=94

X is 94 cm

I hope I've helped!
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What is percentage 1/4 of 200
zimovet [89]

Answer: 50

Step-by-step explanation: 1/4 = 50

                                              2/4 = 100

                                              3/4 = 150

                                               4/4 = 200

4 0
3 years ago
(x+4)(x-8). Express as a trinomial??
Juli2301 [7.4K]

Answer:

x^2-4x-32

Step-by-step explanation:

Hi there!

(x+4)(x-8)

Expand the parentheses

=x(x-8)+4(x-8)\\=x^2-8x+4x-32\\=x^2-4x-32

I hope this helps!

5 0
3 years ago
3. Two of the vertices of an equilateral triangle are (0, -a)
egoroff_w [7]

The third coordinate of the equilateral triangle is (\sqrt3a,0). Ir can be obtained by distance formula.

What is distance formula?

It gives the distance between two coordinates.

Distance formula is given by the following expression:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Consider the third cordinate is (x,0) and x is positive because it is on tight side on the x axis.

Now, since the triangle is equilateral hence, the distance of (x,0) from (0, -a) and (0, a) should be equal to distance between (0, -a) and (0, a).

Now, caculate the distance between (0,-a) and (0, a).\sqrt{(0-0)^2+(-a-a)^2}=2a

Now, distance between (x,0) and (0, a) should be 2a.

\sqrt{(x-0)^2+(0-a)^2}=2a\\\sqrt{x^2+a^2}=2a

Now, square on both the sides.

x^2+a^2=4a^2\\x^2=3a^2\\x=\sqrt3aand -\sqrt3a

But the negative value of x is not possible because the coordinate lies on the right side.

Hence, the third coordinate of equilateral triangle is (\sqrt3a,0).

Learn more about distance formula from the following link:

brainly.com/question/7243416

#SPJ1

5 0
1 year ago
Which are factors of x2 – 4x – 5? Check all that apply. (x – 5) (x – 4) (x – 2) (x + 1) (x + 5)
Pachacha [2.7K]
<span>x^2 – 4x – 5 = (x - 5)(x + 1)
cause
</span>(x - 5)(x + 1) = x^2 -5x +x - 5= x^2 -4x - 5

so (x - 5) and (x + 1) are factors

answer
(x - 5) and (x + 1) 
8 0
3 years ago
Read 2 more answers
Factor completely 625x^4– 81
olga55 [171]

Answer:

(25x^2+9)(5x+3)(5x-3)

Step-by-step explanation:

625x^4-81=(25x^2+9)(25x^2-9)=(25x^2+9)(5x+3)(5x-3)

4 0
3 years ago
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