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3 years ago

Stainless steel is an example of a ____ solution

1 answer:

5 0

I believe the correct answer from the choices listed above is option B. Stainless steel is an example of a solid-solid solution. It is an alloy which is made up of different metals such as carbon, manganese, phosphorus, sulfur, nickel, chromium and others. Hope this answers the question.

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Put the following elements into five pairs of elements that have similar chemical reactivity: F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

kirill115 [55]

Explanation:

Given elements:

F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Elements with the same chemical reactivity will belong to the same group on the periodic table. This implies that elements in the same column will have the same reactivity;

Li and Rb are both alkali metals in group 1

Ca and Sr are both alkali earth metals in group 2

F and Br are halogens in group 7

O and S are group 6 elements

P and Sb are both in group 5 on the periodic table

So these groupings show elements with the same chemical properties.

7 0

2 years ago

The combustion of 1.685 g of propanol (C3H7OH) increases the temperature of a bomb calorimeter from 298.00 K to 302.16 K. The he

AfilCa [17]

Answer:

ΔH = - 2020.57 kJ/mol

Explanation:

Given that :

mass of propanol = 1.685 g

the molar molar mass = 60 g/mol

Thus; the number of moles = mass/molar mass

= 1.685 g/60 g/mol

= 0.028 g/mol

However ;

ΔH = heat capacity C × Δ T

Given that:

The temperature increases from 298.00 K to 302.16 K.

Then ;

Δ T = 302.16 K - 298.00 K

Δ T = 4.16 K

heat capacity C = 13.60 kJ/K

∴

ΔH = 13.60 kJ/K × 4.16 K

ΔH = 56.576 kJ

The equation of the given reaction can be represented as :

$C_3H_7OH_{(l)}+\dfrac{3}{2}O_{2(g)} \to 3CO_{2(g)} +4H_2O_{(l)}$

Thus for 0.028 mol of heat liberated; ΔH = 56.576 kJ

For 1 mole of heat liberated now:

ΔH = 56.576 kJ/0.028 mol

ΔH = 2020.57 kJ/mol

SInce , Heat is liberated, the reaction undergoes an exothermic reaction thus;

ΔH = - 2020.57 kJ/mol

5 0

3 years ago

Read 2 more answers

Predict the products of below reaction, and whether the solution at equilibrium will be acidic, basic, or neutral.

kati45 [8]

Answer: The product of the given reaction is $HNO_{3}$ and the solution at equilibrium will be acidic.

Explanation:

When two or more chemical substances react together then it forms new substances and these new substances are called products.

For example, $3N_{2}O_{5} + 3H_{2}O \rightarrow 6HNO_{3}$

This shows that nitric acid $(HNO_{3})$ is the product formed and it is an acidic substance.

Hence, the solution at equilibrium will be acidic in nature.

Thus, we can conclude that the product of the given reaction is $HNO_{3}$ and the solution at equilibrium will be acidic.

8 0

3 years ago

Write the chemical symbol for three different atoms or atomic cations with 22 electrons

damaskus [11]

Answer:

Explanation:

To write the chemical symbol for an atom or cation with 22 electrons, we must understand some few things about an atom.

An atom is made up of positively charged paticles called protons which are located in the nucleus. The neutrons do not have any charges and are they reside together in the nucleus with the protons.

Electrons are negatively charged particles which orbits the nucleus.

Titanium in its neutral state is the 22nd element on the periodic table and it has 22 electrons.

Vanadium is the the 23rd element on the periodic table. If it loses an electron, it becomes positively charged and it is a cation.

Chromium is the 24th element on the periodic table. A loss of two electrons makes the net electrons remaining on it 22.

The symbols are:

₂₂Ti

₂₃V¹⁺

₂₄Cr²⁺

6 0

3 years ago

2. In Experiment SOL, you investigated the solubility of oxalic acid. Sodium oxalate, Na2C2O¬4, is the sodium salt of this acid.

AnnZ [28]

Answer:

Sodium oxalate is a basic salt. In water it can be dissolved and dissociated.

The oxalic acid in water has two dissociations.

Explanation:

Na2C2O4 ---> 2Na+ + C2O4-2

Sodium oxalate is the conjugate base of a weak acid. In water this salt, dissociates completely giving rise to the sodium and oxalate ions. As Na+ comes from a strong base, in water it does not produce hydrolysis while oxalate does react in water, because it takes a proton from it and it generates a basic hydrolysis releasing OH-.

C2O4-2 + H2O ⇄ HC2O4- + OH-

In water the salt is basic. The pH of an aqueous solution of this salt is basic, since OH- is generated.

The HC2O4- has a second hydrolisis, it takes another proton from water to form oxalic acid.

HC2O4- + H2O ⇄ H2C2O4 + OH-

The oxalic acid acts as a weak acid, it can release 2 protons to water, to make oxalate (its conjugate base).

H2C2O4 + H2O ⇄ H3O+ + HC2O4-

HC2O4- + H2O ⇄ H3O+ C2O4-2

The HC2O4- acts as an ampholyte since it accepts and delivers protons simultaneously.

6 0

3 years ago