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qaws [65]
3 years ago
7

What is the order of decreasing ionization energy?

Chemistry
1 answer:
Hatshy [7]3 years ago
6 0
Your answer would be 3!!

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Which of the following chemical reactions is the only reaction shown that would be predicted to occur based on the activity seri
Novosadov [1.4K]

B. Mn + NiBr₂  →  Ni + MnBr₂

Explanation:

The reaction that can be predicted of all is Mn + NiBr₂  →  Ni + MnBr₂.

The activity series is used to predict the products of single displacement reactions.

The series ranks metals in order of their reactivity. Those higher up in the series are highly reactive metals. Those at the bottom are slightly to non-reactive metals.

For a single displacement reaction to occur, a metal higher up in the activity series displaces one that is lower in the series.

  Reaction A will not occur, Ba is higher in the series

  Reaction C will not occur, Pt and Au are unreactive

  Reaction D will not occur as Zn is lower in the series

Mn is higher in the reactivity series and it will displace Ni from the solution.

Learn more:

Synthesis reaction brainly.com/question/4216541

#learnwithBrainly

7 0
3 years ago
What is the element that is in period 5 and group 3?
rjkz [21]

Answer:

Rubidium

Rubidium is the first element placed in period 5. 

6 0
3 years ago
Which statement explains how the Sun influences movement in the Earth's atmosphere?
MakcuM [25]
Correct Answer: The Sun heats the Earth unevenly; this heating pattern then causes convection currents in the atmosphere.
4 0
3 years ago
The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58
Umnica [9.8K]

Answer:

22.27 °C = ΔT

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass = 28 g

heat absorbed = 58 cal

specific heat of copper =  0.093 cal/g .°C

temperature change =ΔT= ?

Solution:

Q = m × c × ΔT

58 cal = 28 g × 0.093 cal /g.°C × ΔT

58 cal = 2.604 cal.°C × ΔT

58 cal / 2.604 cal .°C = ΔT

22.27 °C = ΔT

5 0
3 years ago
I NEED HELP ASAP PLEASE
scZoUnD [109]
I think it’d be C. I’m not 100% if it is tho
8 0
3 years ago
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