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lilavasa [31]
3 years ago
8

7. A pastry chef bakes a cheesecake. What is this an example of?* O Physical Change O Physical Property Chemical Change Chemical

Property​
Chemistry
1 answer:
Airida [17]3 years ago
4 0

Answer:

Chemical Change

Explanation:

This is a chemical change since the chemical structure of the components in the cheesecake changes when it is baked.  This means that you can't make a baked cheesecake unbaked.

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Which is the correct complete ionic equation for the reaction of
cricket20 [7]

Answer:

b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)

Explanation:

The equation is given as;

2HCl(aq) + Zn(s) + H2(g) + ZnCl2(aq)

In writing an ionic equation, only the aqueous compounds dissociates into ions. This means HCl and ZnCl2 would dissociate to form ions.

This is given as;

2H+  +  2Cl-  + Zn(s) --> H2(g) + Zn2+  + 2Cl-

The correct option is;

b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)

8 0
2 years ago
A bottle containing 415 g of cleaning solution is used to clean hospital equipment. If the cleaning solution has a specific grav
neonofarm [45]

Answer: 483 mL of the cleaning solution are used to clean hospital equipment

Explanation:

The question requires us to calculate the volume, in mL, of solution is used to clean hospital equipment, given that 415g of this solution are used and the specific gravity of the solution is 0.860.

Measurements > Density

Specific gravity is defined as the ratio between the density of a given substance to the density of a reference material, such as water:

Specific\text{ gravity = }\frac{density\text{ of substance}}{density\text{ of reference substance}}

The density of a substance is defined as the ratio between the mass and the volume of this substance:

density=\frac{mass}{volume}

Considering the reference substance as water and its density as 1.00 g/mL, we can determine the density of the substance which specific gravity is 0.860:

0.860=\frac{density\text{ of substance}}{1.00g/mL}\rightarrow density\text{ of substance = 0.860g/mL}

Thus, taking water as the reference substance, we can say that the density of the cleaning solution is 0.860 g/mL.

Now that we know the density of the cleaning solution (0.860 g/mL) and the mass of solution that is used to clean hospital equipment (415g), we can calculate the volume of solution that is used to clean the equipment:

\begin{gathered} density=\frac{mass}{volume}\rightarrow volume=\frac{mass}{density} \\  \\ volume=\frac{415g}{0.860g/mL}=483mL \end{gathered}

Therefore, 483 mL of the cleaning solution are used to clean hospital equipment.

6 0
1 year ago
How to balance the question?​
umka21 [38]

Answer:

CH4 + 2O2 —> CO2 + 2H2O

CH4 + 2O2

C = 1

H = 4

O = 2 ×2 = 4

__o_o___

CO2 + 2H20

C = 1

H = 2 × 2 = 4

O = 2 + 2 = 4

So ; 1 C , 4 H , 4 O

I hope I helped you^_^

4 0
2 years ago
The rate constant for this second‑order reaction is 0.190 M − 1 ⋅ s − 1 0.190 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product
Mamont248 [21]

Answer:

9.1 seconds

Explanation:

Given that for a second order reaction

1/[A]t = kt + 1/[A]o

Where [A]t= concentration at time = t= 0.340M

[A]o= initial concentration = 0.820M

k= rate constant for the reaction=0.190m-1s-1

t= time taken for the reaction (the unknown)

Hence;

(0.340)^-1 = 0.190×t + (0.820)^-1

t= (0.340)^-1 - (0.820)^-1/0.190

t= 9.1 seconds

Hence the time taken for the concentration to decrease from 0.840M to 0.340M is 9.1 seconds.

5 0
3 years ago
_ is used as construction materials.
musickatia [10]

Answer:

Q1) Bedrock

Q2) Topsoil

Q3) Desertification

Explanation:

YO NOW YOU HAVE TO ASNWER MY QUESTION AND SHOW UR WORK BROOOOOOOOOOOOOOOOOOOOOOOO DO IT ASAP

6 0
3 years ago
Read 2 more answers
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