Predict whether each reaction proceeds predominately by substitution, elimination, or whether the two combined. Write structure
1 answer:
Answer:
Reaction 1 - elimination
Reaction 2- substitution
Reaction 3- the two combined
Explanation:
In the first reaction, a strong base, KOH is used in the reaction. Remember that when a tertiary alkyl halide is the substrate, the use of a strong base leads to the domination of E1 mechanism over SN1 mechanism, hence the product shown in the image attached.
In reaction 2, the secondary alkyl halide must undergo an SN2 substitution since an aprotic solvent (THF) is used. This leads to inversion of configuration as shown in the product.
In reaction 3, CN^- is both a strong base and a good nucleophile hence a mixture of substitution and elimination products are formed depending on the nature of the alkyl halide.
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<u>Answer:</u> The freezing point of solution is 2.6°C
<u>Explanation:</u>
To calculate the depression in freezing point, we use the equation:
Or,
where,
=
Freezing point of pure solution = 5.5°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal freezing point depression constant = 5.12 K/m = 5.12 °C/m
= Given mass of solute (anthracene) = 7.99 g
= Molar mass of solute (anthracene) = 178.23 g/mol
= Mass of solvent (benzene) = 79 g
Putting values in above equation, we get:
Hence, the freezing point of solution is 2.6°C