Predict whether each reaction proceeds predominately by substitution, elimination, or whether the two combined. Write structure
1 answer:
Answer:
Reaction 1 - elimination
Reaction 2- substitution
Reaction 3- the two combined
Explanation:
In the first reaction, a strong base, KOH is used in the reaction. Remember that when a tertiary alkyl halide is the substrate, the use of a strong base leads to the domination of E1 mechanism over SN1 mechanism, hence the product shown in the image attached.
In reaction 2, the secondary alkyl halide must undergo an SN2 substitution since an aprotic solvent (THF) is used. This leads to inversion of configuration as shown in the product.
In reaction 3, CN^- is both a strong base and a good nucleophile hence a mixture of substitution and elimination products are formed depending on the nature of the alkyl halide.
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Answer: The value of for chloroform is
when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.
Explanation:
Given: Moles of solute = 0.793 mol
Mass of solvent = 0.758
As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.
Now, the values of is calculated as follows.
where,
i = Van't Hoff factor = 1 (for chloroform)
m = molality
= molal boiling point elevation constant
Substitute the values into above formula as follows.
Thus, we can conclude that the value of for chloroform is
when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.