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kotykmax [81]
3 years ago
5

Why is cosine positive in the 4th quadrant and sine isn’t?

Mathematics
1 answer:
kari74 [83]3 years ago
8 0

Answer:

Because sine can only be positive in quadrant II according to the CAST rule.

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the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


4 0
3 years ago
Find 62(9) . Express your answer as a fraction in simplest form
Bas_tet [7]

Answer:

558/1

Step-by-step explanation:

7 0
3 years ago
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PLEASE HELP ASAP. I HAVE A VERY IMPORTANT TEST AND I NEED HELP
Katarina [22]

Answer:

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Step-by-step explanation:

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3 years ago
I need help with this I put this out 3 times I need help
anzhelika [568]
Prompt
What is a row?
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Which is the quotient for
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Step-by-step explanation:

D

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