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erastova [34]
2 years ago
8

Please answer BOTH questions

Mathematics
1 answer:
Lera25 [3.4K]2 years ago
4 0

Answer:46.28, 193.75

Step-by-step explanation:

The first one you add (((2.5+4.7)x3.05)+1.18)x2. And the second one you (7.50+0.25)x25.

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What is the third angle of a triangle if the other two are (3x-20)° and (4x+10)°​
Karolina [17]

Answer:

The other angle is 190-7x.

Step-by-step explanation:

Angles in a triangle add up to 180 degrees.

Let A be the third angle.

A + (3x-20) + (4x+10) = 180

A = 180 - (3x - 20) - (4x + 10) = 190 - 7x

8 0
3 years ago
Maria had $100 at the beginning of summer vacation. She plans to mow lawns and charge $20 per lawn. Which graph could be used to
Illusion [34]

Answer:

Line graph

Step-by-step explanation:

7 0
3 years ago
Help pleaseeeeeeeeeeeee
jeyben [28]

Answer:

B

Step-by-step explanation:

-2 is greater than -3

3 0
3 years ago
Read 2 more answers
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GalinKa [24]

Answer:

C:

Step-by-step explanation:

7 0
3 years ago
Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i
bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1)  with respective to 'x'

\frac{dx}{dt} = 1+cost

differentiating equation (2)  with respective to 'y'

\frac{dy}{dt} = -sint

The length of curve is

\int\limits^\pi_\pi  {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt

\int\limits^\pi_\pi  \,   {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

\int\limits^\pi_\pi  \,   {\sqrt{(2+2cost } } \, dt

\sqrt{2} \int\limits^\pi_\pi  \,   {\sqrt{(1+1cost } } \, dt

again using formula, 1+cost = 2cos^2(t/2)

\sqrt{2} \int\limits^\pi _\pi  {\sqrt{2cos^2\frac{t}{2} } } \, dt

Taking common \sqrt{2} we get ,

\sqrt{2}\sqrt{2}  \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt

2(\int\limits^\pi _\pi  {cos\frac{t}{2} } \, dt

2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }

length of curve = 4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))

length of the curve is = 4(1+1) = 8

<u>conclusion</u>:-

The arrow of the direction or the length of curve = 8

7 0
3 years ago
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