B. First off , standard form of a 2nd degree equation is Ax^2 + Bx + C. So look at the coefficient of Ax^2 which is -2.
If positive, the parabola opens up and has a minimum.
If negative, the parabola opens down and has a maximum.
A. To find the vertex (in this case maximum),
Graph the equation -OR—
make a table. — OR—
Find the zeroes and find the middle x-value
-2x^2 - 4x + 6
-2(x^2 +2x - 3 = 0
-2 (x - 1) ( x + 3)=0
x - 1 = 0. x + 3 = 0
x = 1. x = -3. So halfway would be at (-1, __).
Sub in -1 into original equation -2x^2 -4x + 6 … -2(-1)^2 -4(-1) + 6 = -2 +4 +6 = 8
So the vertex is (-1,8)
I do not need any snarky remarks from you. I was trying to help. FOR EXAMPLE what am I solving for? Y intercept, X intercept. You don't get to get angry with me because I'm asking a simple question girl.
50
(e= 10 to the power of)
6.6e-2/3.3e-4= 3.3e4/6.6e2=0.5e2= 0.5x10^2=50
Answer:
1.56
0.52
Step-by-step explanation:
Answer:
102cm^2 - hope this helps
Step-by-step explanation:
find the area of the rectangle first in the middle
which equals 6 x 13 = 78cm^2
then find the traingles on the side
(6 x 4) / 2 = 12
there are 2 traingles so it would be 12 + 12 = 24
so all together the area would be 78 + 24 = 102cm ^2
