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chubhunter [2.5K]
3 years ago
9

Half of a liter is equal to 16.91 ounces. How many ounces are there in 3 liters?

Mathematics
1 answer:
Scrat [10]3 years ago
4 0

Answer: 101.46 ounces in 3 liters


Step-by-step explanation:

To do this problem in the easiest way, you take your half liter and double your answer to make it one liter.

16.91 x 2= 33.82 ( 1 liter)

Now since you have one liter and you need 3 liters, all you do is triple your last answer to get 3 liters.

33.82 x 3= 101.46 ( 3 liters)


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A brick has a volume of 2,300 mL and a mass of 3.4 kg. what is the density of the brick
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3 years ago
How can you get 3/3 -1/6?
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9514 1404 393

Answer:

  5/6

Step-by-step explanation:

Addition or subtraction of fractions requires a common denominator. The value 3/3 can be multiplied by 2/2 to give 6/6, which has the same denominator as the other fraction.

  \dfrac{3}{3}-\dfrac{1}{6}=\dfrac{3\cdot2}{3\cdot2}-\dfrac{1}{6}\\\\=\dfrac{6}{6}-\dfrac{1}{6}=\dfrac{6-1}{6}=\boxed{\dfrac{5}{6}}

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The principal at Riverside High School would like to estimate the mean length of time each day that it takes all the buses to ar
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Answer:

C) 11

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    

And on this case we have that ME =7 and we are interested in order to find the value of n, if we solve n from the last equation we got:

n=(\frac{z_{\alpha/2} s}{ME})^2  

And replacing the values that we got we have:

n=(\frac{1.64(14)}{7})^2 =10.758 \approx 11

C) 11

8 0
3 years ago
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