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Ugo [173]
3 years ago
14

Which trig ratio should you use to find the given side?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0

Answer:

D. cosine

Step-by-step explanation:

As it can be seen in the figure, the triangle ABC is a right-angled triangle with Angle C = 90 degree.

In a right angle triangle, there is a formula as following:

<em>cosine (of an acute angle) = length of  adjacent side/ length of hypotenuse</em>

In the figure, the point of angle B and length of hypotenuse AB are given.

We have to calculate x - length of the given side. As BC is the adjacent side of angle B

=> we can use the above formula to calculate x

So that we can use cosine

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What percent of 80 is 28
serious [3.7K]

Answer:

35%

Step-by-step explanation:

easy way to remember: \frac{28}{80} *1 00

= 0.35 *100

= 35%

5 0
3 years ago
Read 2 more answers
What is the equation in point slope form of a line that passes through the point (–8, 2) and has a slope of 1/2?
Kamila [148]
Point slope equation: 
y-y1=m(x-x1) 
m=slope

So we simply plug in our given information: 
x1=-8 
y1=2
m=1/2

y-2=1/2(x-(-8)  

2 minus signs next to each other make a positive 

Final answer: 
y-2=1/2(x+8)
6 0
3 years ago
Use four rectangles to estimate the area between the graph of the function f(x) = V3x + 5 and the x-axis on the interval[0, 4] u
yuradex [85]

Answer:

  12.123

Step-by-step explanation:

You want the area under the curve f(x) = √(3x+5) on the interval [0, 4] estimated using the left sum and four subintervals.

<h3>Riemann sum</h3>

When the interval [0, 4] is divided into four equal parts, each has unit width. That means the area of the rectangle defined by the curve and the interval width will be equal to the value of the curve at the left end of the interval.

The area we want is the sum ...

  f(0) +f(1) +f(2) +f(3)

As the attachment shows, that sum is ...

  area ≈ 12.123 . . . square units

__

<em>Additional comment</em>

The table values in the attachment are rounded to 7 decimal places. Trailing zeros are not shown. Actual values used have 12 significant digits, as the total shows.

Such a sum is called a Riemann sum, named for a German mathematician. Four such sums are commonly used, and further refinements are possible. Those are the left sum (as here), the right sum, the midpoint sum, and a sum using a trapezoidal approximation of the rectangle area.

For left, right, and midpoint sums, n function values are required for n subintervals. When the trapezoidal approximation is used, n+1 function values are required.

7 0
1 year ago
what is consecutive whole numbers? I have to write an algebraic expression for the sum of three consecutive whole numbers... :(
Agata [3.3K]

Answer:

Consecutive whole numbers (or integers) are numbers that directly follow one another.

Eg: 1, 2, 3, 4, 5 are consecutive whole numbers.

Step-by-step explanation:

Three consecutive even integers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108.

or

let the three consecutive whole numbers is x, x+1,and x+2

x + x+1 + x+2 = 4+2(x+1)

3x+3=4+2x+2

3x-2x=6-3

x=3

the other two numbers are 3+1=4,and 3+2=5

so the three numbers are 3,4 and 5

7 0
3 years ago
UPPER AND LOWER BOUNDS - PLEASE HELP!
Marianna [84]
Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg

Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm

Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg

Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm

Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm

Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm

Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5

Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm

Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
8 0
3 years ago
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