Answer:
(2,-5)
Step-by-step explanation:
Hope it helps! :)
An=-5n+260
A40=60
So the Awnser is 60
(Hope this helped!!)
Answer:
The probability is 0.9211
Step-by-step explanation:
Let's call K the event that the student know the answer, G the event that the student guess the answer and C the event that the answer is correct.
So, the probability P(K/C) that a student knows the answer to a question, given that she answered it correctly is:
P(K/C)=P(K∩C)/P(C)
Where P(C) = P(K∩C) + P(G∩C)
Then, the probability P(K∩C) that the student know the answer and it is correct is:
P(K∩C) = 0.7
On the other hand, the probability P(G∩C) that the student guess the answer and it is correct is:
P(G∩C) = 0.3*0.2 = 0.06
Because, 0.3 is the probability that the student guess the answer and 0.2 is the probability that the answer is correct given that the student guess the answer.
Therefore, The probability P(C) that the answer is correct is:
P(C) = 0.7 + 0.06 = 0.76
Finally, P(K/C) is:
P(K/C) = 0.7/0.76 = 0.9211
Answer:
11 in
Step-by-step explanation:
Standard paper is 11 x 8 inches
<span>1) if 2 times the wind speed is increased by 2, the wind speed is still less
than 46 km/h.
=> 2x + 2 < 46
2) Twice the wind speed minus 27 is greater than 11 km/h.
=> 2x - 27 > 11
Part A: Create a compound inequality to represent the wind speed range.
(3 points)
from 2x + 2 < 46
=> 2x < 44
=> x < 22
from 2x - 27 > 11
=> 2x > 11 + 27
=> 2x > 38
=> x > 19
The set of inequalities is
2x + 2 <46
2x - 27 > 11
The solution is x < 22 and x > 19, which is:
19 < x < 22 <----- answer
Part B: Can the wind speed in this town be 20 km/h? Justify
your answer by solving the inequalities in Part A. (3 points)
Yes, the wind speed can be 20 km/h, because the solution of the inequality is the range (19,22).
Part C:
The average wind speed in another town is 23 km/h, but the actual wind
speed is within 4 km/h of the average. Write and solve an inequality to
find the range of wind speed in this town.
x ≥ 23 - 4 => x ≥ 19
x ≤ 23 + 4=> x ≤ 27
=> 19 ≤ x ≤ 27
=> [19,27]
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