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ikadub [295]
4 years ago
14

An onject is.launched from platform. Its height (in meters) x seconds after the launch is modeled by h(x) =-5(x+1)(×-9) How many

seconds after launch will the object hit the ground
Mathematics
1 answer:
Serga [27]4 years ago
4 0

Answer:

9 seconds

Step-by-step explanation:

When the object is on the ground it's height = 0

Equate h(x) = 0, hence

- 5(x + 1)(x - 9) = 0

equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x - 9 = 0 ⇒ x = 9

x > 0 hence x = 9

The object hits the ground 9 seconds after being launched


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3 years ago
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Angelina_Jolie [31]

Answer:

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Step-by-step explanation:

<u>**I assume that side WX in my diagram (attached as an image below) is the value of C that we're looking for. ALSO, the sizes and lengths of the parallelograms are NOT to scale.**</u>

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With that in mind, we can apply this ratio to find WX.

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7 0
3 years ago
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jeka94

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