Segment NO is parallel to the segment KL.
Solution:
Given KLM is a triangle.
MN = NK and MO = OL
It clearly shows that NO is the mid-segment of ΔKLM.
By mid-segment theorem,
<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>
⇒ NO || KL and 
Therefore segment NO is parallel to the segment KL.
Answer:
(This is a example since you don’t have anything to round to)
Example Answer if the radius is 4 - 50.24
Step-by-step explanation:
Example Radius : 4
Area : 3.14
We have the mulitiply 3.14 times The Example Radius 2 times because The diameter of a circle is 2 times its radius.
( 3.14 x 4 x 4) 50.24
If you know the diameter, it’s a half or 1/2 as large.
Therefore, if the radius was 4, it would be 50.24.
Youre welcome :)
Area=1/2 times base times height
note:bh=base times height
a=1/2bh
b=width
h=-4+2w
h=2w-4
subsitute
a=1/2w(2w-4)
a=1/2(2s^2-4w)
a=w^2-2w
a=63
63=w^2-2w
subtract 63 from both sdies
0=w^2-2w-63
factor
find what 2 numbers multiply to get -63 and add to get -2
the numbers are -9 and 7
so
0=(w-9)(w+7)
if xy=0 then x and/or y=0
so
w-9=0
w+7=0
solve each
w-9=0
add 9 to both sdies
w=9
w+7=0
subtract 7 from both sides
w=-7
width cannot be negative so this can be discarded
width=9
subsitute
l=2w-4
l=2(9)-4
l=18-4
l=14
legnth=14 in
width/base=9 in
Answer:
6 possible integers
Step-by-step explanation:
Given
A decreasing geometric sequence

Required
Determine the possible integer values of m
Assume the first term of the sequence to be positive integer x;
The next sequence will be 
The next will be; 
The nth term will be 
For each of the successive terms to be less than the previous term;
then
must be a proper fraction;
This implies that:

<em>Where 7 is the denominator</em>
<em>The sets of </em>
<em> is </em>
<em> and their are 6 items in this set</em>
<em>Hence, there are 6 possible integer</em>