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tatyana61 [14]
3 years ago
11

A video game company surveys a random sample of 225 of its best customer and finds that the average gamer spends $606 a year on

games, with a standard deviation of $62. Another company is also interested in the amount game consumers spend, and surveys a random sample of 250 gamers, over all interest levels, and finds that the average gamer spends $250 a year on games, with a standard deviation of $15. Why is the second survey more believable than the first?
Mathematics
1 answer:
victus00 [196]3 years ago
6 0

Answer:

Multi facets

Step-by-step explanation:

First company surveys best customers so they are highest spending

First company standard deviation is high @ $62 so their spends are $606 a year plus or minus $180 (rounded up)

Second company has a Random sample so includes all customers

Second company has larger number of responses

Second company has a range of plus or minus $40

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point a has the coordinates(2,5) point B has the coordinates (6,17) how long is segment ab in simplified radical form
IRISSAK [1]

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4\sqrt{10}

Step-by-step explanation:

We have been given that point A has the coordinates(2,5) point B has the coordinates (6,17).

To find the length of segment AB we will use distance formula.

\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Upon substituting coordinates of point A and point B in distance formula we will get,

\text{Distance between point A and point B}=\sqrt{(6-2)^2+(17-5)^2}

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3 years ago
Mr.Scott weekly salary is $37 less than Mr. Khanna's. If Scott weekly salary is $584, what is Khanna's weekly salary?​
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Step-by-step explanation:

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\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho

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Given the series \sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}

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\frac{a_n_+_1}{a_n} =  \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\

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note that any constant dividing infinity is equal to zero

|\frac{1+2/\infty+1/\infty^2}{5}|\\\\

\frac{1+0+0}{5}\\ = 1/5

\rho = 1/5

Since The limit of the sequence given is less than 1, hence the series converges.

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3 years ago
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