All categories

3 years ago

I need help please! It would be very helpful ;) if ya helped me 0-0

Mathematics

1 answer:

Anna [14]3 years ago

8 0

Answer:

im thinking B. or C.

Step-by-step explanation:

again not sure

again sorry if wrong

You might be interested in

jada is using a computer’s random number generator to produce 6 random whole numbers between 1 and 100 so she can use a random s

nikdorinn [45]

Step-by-step explanation:

The random numbers are selected randomly. Just because they happen to be 6 numbers in a row does not mean that they were not. If she is confident in the random number generator, which can be assumed, then the random numbers were still randomly selected and can be used. To regenerate would be a mistake because Jada is then picking and choosing which random numbers are chosen, defeating the purpose of a random number generator

7 0

3 years ago

What’s the correct answer ??

Artyom0805 [142]

Im finding it...

Step-by-step explanation:

6 0

3 years ago

What is this answer?

QveST [7]

Answer:

g>-3

Step-by-step explanation:

You divide -5 on both sides to get -3.

4 0

3 years ago

A box on a 20 degree incline is shown with vectors radiating from a point in the center of the box. The first vector points up a

Finger [1]

The images to solve this problem is in the attachment.

Answer: $F_{fs}$ = 671.0 N; $F_{N}$ = 300 N

Step-by-step explanation: From the image in the attachment and knowing that the box is in equilibrium, i.e., the "sum" of all the forces is 0, it is possible to conclude that:

$F_{fs}$ = $F_{gx}$ and $F_{N}$ = $F_{gy}$

Using trigonometry, shown in the second attachment, the values for each force are:

Force of Static Friction

sin 20° = $\frac{F_{gx} }{F_{g} }$

$F_{gx}$ = $F_{g}$ . sin(20)

$F_{gx}$ = 735.0.913

$F_{gx}$ = 671.0

Normal Force

cos 20° = $\frac{F_{gy} }{F_{g} }$

$F_{gy}$ = $F_{g}$ . cos (20)

$F_{gy}$ = 735.0.408

$F_{gy}$ = 300

The force of static friction is 671N and normal force is 300N

8 0

3 years ago

Read 2 more answers

Can someone tell me how to approach this, I could care less about the answer I just want to know how to solve this without Desmo

kipiarov [429]

Answer:

the vertex is at (4, -14)

Step-by-step explanation:

Review "quadratic equations." These have three terms, and the highest power of x is x^2. We need to identify the coefficients of the x^2, x and x^0 terms to get info needed to identify the axis of symmetry.

Given f(x) = x^2 - 8x + 2, we see that these coefficients are 1, -8 and 2.

The formula for the axis of symmetry is x = - ------

which here is x = -(-8)/[2*1], or x = 8/2 or x = 4: the axis of symmetry.

To find the y-coordinate of the vertex, evaluate the function at x = 4:

f(4) = 4^2 - 8(4) + 2 = 16 - 32 + 2, or f(4) = -14.

Thus, the vertex is at (4, -14). The graph is that of a parabola that opens up, and the parabola is symmetric about the vertical line x = 4.

4 0

3 years ago