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RideAnS [48]
2 years ago
6

What is the measure of angle B in degrees? A) 30 B) 45 C) 60 D) 90

Mathematics
1 answer:
Triss [41]2 years ago
5 0

Answer:

its a 30 my friend and if its not a then choose b hope this helped

Step-by-step explanation:

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PLS HELP<br><br><br> Which equation describes the function shown in the table? <br>​
evablogger [386]

Answer:

The first one

Step-by-step explanation:

Because it already give you the y-intercept and you can solve x by doing 4 to 7 have to add 3 and x only have to add 1. It will give you a slope 3/1, so it is 3.

y=3x+1

7 0
2 years ago
Which expression is equivalent to (4−3)−6?<br><br> 418<br> 43<br> 4−18<br> 4−9
Assoli18 [71]

(4-3)-6 = 1-6 = -5

4-9 = -5

The answer is 4-9

8 0
2 years ago
Read 2 more answers
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
NEED ASAP<br><br> 1. Find the distance between (3√3, √11) and (−5√3, 5√11)
VLD [36.1K]

Answer:\sqrt20

Step-by-step explanation

7 0
2 years ago
PLEASE NO LINKS OR SITES!!!! JUST ANSWERS. THANK YOU!
lutik1710 [3]

Answer:

F=-9

Hope This Helps!

6 0
2 years ago
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