i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point.
So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL
ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the steps
Answer:
109
Step-by-step explanation:
I am smart
It’s is 28 I will explain how to do it first times 8x6 then subtract 12 and 4 and the two numbers u get add them and then divide it by 2
We know that
The difference of two squares<span> is a squared number subtracted from another squared number. Every difference of squares may be factored according to the identity</span>
<span>
(A</span>²-B²)=(A+B)*(A-B)
<span>so
the answer is
</span><span>49m2 − 81n4
</span>49m2 − 81n4=(7m+9n²)*(7m-9n²)
Atleast 302.5 can fit on the shelves
