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4 years ago

10.0 ml of 1.00 M HCl neutralized 20.0 ml of a NaOH solution. What was the molarity of the NaOH?

Chemistry

1 answer:

Viefleur [7K]4 years ago

6 0

Answer:

0.500 M

Explanation:

The balanced equation for the neutralization reaction is as follows

NaOH + HCl —> NaCl + H2O

Molar ratio of NaOH to HCl is 1:1

Number of moles of NaOH reacted is equal to the number of HCl moles

We can use the following equation

c1v1 = c2v2

Where c1 is concentration and v1 is volume of HCl

c2 is concentration and v2 is volume of NaOH

Substituting the values

1.00 M x 10.0 mL = c2 x 20.0 mL

c2 = 0.500 M

Concentration of NaOH is 0.500 M

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3 years ago

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3 years ago

An inverted pyramid is being filled with water at a constant rate of 45 cubic centimeters per second. The pyramid, at the top, h

vaieri [72.5K]

Answer:

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

Explanation:

Length of the base = l

Width of the base = w

Height of the pyramid = h

Volume of the pyramid = $V=\frac{1}{3}lwh$

We have:

Rate at which water is filled in cube = $\frac{dV}{dt}= 45 cm^3/s$

Square based pyramid:

l = 6 cm, w = 6 cm, h = 13 cm

Volume of the square based pyramid = V

$V=\frac{1}{3}\times l^2\times h$

$\frac{l}{h}=\frac{6}{13}$

$l=\frac{6h}{13}$

$V=\frac{1}{3}\times (\frac{6h}{13})^2\times h$

$V=\frac{12}{169}h^3$

Differentiating V with respect to dt:

$\frac{dV}{dt}=\frac{d(\frac{12}{169}h^3)}{dt}$

$\frac{dV}{dt}=3\times \frac{12}{169}h^2\times \frac{dh}{dt}$

$45 cm^3/s=3\times \frac{12}{169}h^2\times \frac{dh}{dt}$

$\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times h^2}$

Putting, h = 4 cm

$\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times (4 cm)^2}$

$=13.20 cm/s$

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

3 0

3 years ago