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Nostrana [21]
3 years ago
11

The density of liquid mercury is 13.69 g/cm^3. How many atoms of mercury are in a 15.0 cm^3 sample? Use "E" for "x10" and use si

g figs.
Chemistry
1 answer:
balu736 [363]3 years ago
6 0
The formula is  m = D x V
D = <span>13.69 g/cm^3.
</span>V = <span>15.0 cm^3 
the mass of the liquid mercury is m= </span>13.69 g/cm^3 x 15.0 cm^3 = 195g
the molar mass of Hg is 200,
1 mole of Hg = 200g Hg, so #mole of Hg= 195 / 200 = 0.97 mol
but we know that
 1 mole  = 6.022 E23 atoms
0.97 mole=?

6.022 E23 atoms x 0.97 / 1 mole = 5.84 E23 atoms
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gogolik [260]

Answer: A) 3.21 g

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side.

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We are given:

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Applying law of conservation of mass, we get:

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7 0
3 years ago
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arlik [135]

Answer:

One mole is the Avogadro's number of particles (atoms, molecules, ions or electrons) in a substance. Converting to moles is fairly easy because the conversion is always the same.

8 0
3 years ago
How many atoms below?
zlopas [31]

Answer:

44

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6 0
3 years ago
What is the new concentration of 25.0mL added to 125.0mL of 0.150M
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The new concentration is 0.125 M.

Explanation:

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8 0
2 years ago
Read 2 more answers
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