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3 years ago

How many molecules are present in 1 teaspoon of sucrose if its mass is 4.10g? show your work

1 answer:

7 0

4.10 g C12H22O11 * ( 1 mol / 342.2965 g ) * ( 6.022x10^23 / 1 mol ) = 7.2107077x10^21 molecules = 7.21x10^21 molecules

Convert grams to moles using the molar mass ( g/mol ).

Use Avogadro's constant ( 6.022x10^23 ) to get the quantity of molecules from the amount of moles.

Revise answer to have the correct number of significant figures ( the smallest amount of digits in any number in the problem is the amount of significant figures your answer should have ).

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The rotten smell of a decaying animal carcass is partially due to a nitrogen-containing compound called putrescine. Elemental an

balu736 [363]

The empirical formula is $C_2H_6N$ .

Explanation:

Putrescine has the elements like Carbon, Nitrogen and Hydrogen present in them. So in order to determine the empirical formula, we first have to find the number of moles present in the putrescine. As the percentage of C, H and N present in the chemical is given as 54.50%, 13.73% and 31.77%, we assume that 100 g of Putrescine is taken as sample.

Then the mass of C, H and N present in Putrescine will be 54.50 g, 13.73 g and 31.77 g. We know that the molar mass of C is 12 g/mol, H is 1 g/mol and N is 14 g/mol. So divide the mass with the molar mass of the respective elements to determine the number of moles of these elements present in the sample.

$No.\ of\ moles\ of\ C=\frac{\text { Mass of } C}{\text { Molar mass of } C}=\frac{54.50 \mathrm{g}}{12 \mathrm{g} / \mathrm{mol}}=4.54\ moles$

Similarly, the number of moles of H and N present is determined.

$\text { No. of moles of } H=\frac{\text { Mass of } H}{\text { Molar mass of } H}=\frac{13.73 \mathrm{g}}{1 \mathrm{g} / \mathrm{mol}}=13.73 \text { moles }$

$No.\ of\ moles\ of\ N=\frac{\text { Mass of } N}{\text { Molar mass of } N}=\frac{31.77 \mathrm{g}}{14 \mathrm{g} / \mathrm{mol}}=2.27\ moles$

Then the empirical formula can be determined by dividing the number of moles of all elements with the least number of moles that is 2.27.

$\begin{aligned}&\text { No. of atoms of } C=\frac{4.54}{2.27}=2\\&\text { No. of atoms of } H=\frac{13.73}{2.27}=6\\&\text { No. of atoms of } N=\frac{2.27}{2.27}=1\end{aligned}$

So, the empirical formula is $C_2H_6N$ .

3 0

3 years ago

Water's heat of fusion is 80. cal/g , its specific heat is 1.0calg⋅∘C, and its heat of vaporization is 540 cal/g . A canister is

Pani-rosa [81]

294400 cal The heating of the water will have 3 phases 1. Melting of the ice, the temperature will remain constant at 0 degrees C 2. Heating of water to boiling, the temperature will rise 3. Boiling of water, temperature will remain constant at 100 degrees C So, let's see how many cal are needed for each phase. We start with 320 g of ice and 100 g of liquid, both at 0 degrees C. We can ignore the liquid and focus on the ice only. To convert from the solid to the liquid, we need to add the heat of fusion for each gram. So multiply the amount of ice we have by the heat of fusion. 80 cal/g * 320 g = 25600 cal Now we have 320 g of ice that's been melted into water and the 100 g of water we started with, resulting in 320 + 100 = 420 g of water at 0 degrees C. We need to heat that water to 100 degrees C 420 * 100 = 42000 cal Finally, we have 420 g of water at the boiling point. We now need to pump in an additional 540 cal/g to boil it all away. 420 g * 540 cal/g = 226800 cal So the total number of cal used is 25600 cal + 42000 cal + 226800 cal = 294400 cal

6 0

3 years ago

GUYS PLEASE HELP ME I BEG YOU

Hoochie [10]

Answer:

an object is a rest upon a table

5 0

3 years ago

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Which part of Earth most likely has the highest albedo value?

andre [41]

Uhhh pretty sure B

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3 0

3 years ago

How many molecules of manganese (IV) sulfate are there if you are given 542.32g?

MAVERICK [17]

Answer:

3.47 mol MnSO4

Explanation:

54.94 + 32.07 + (16 × 4) = 151.01g/mol MnSO4

542.32g / 151.01g/mol = 3.47 mol MnSO4

5 0

3 years ago