as you already know, the area of a rectangle is just length*width, so is just the product of those two.
Unknown. C is the hypotenuse, but this problem is solvable.
Answer:
8x^3-7x^2-11x+9
Step-by-step explanation:
(8x^3-5x-1)-(7x^2+6x-10)
remove unnesasary ( )
8x^3-5x-1 -(7x^2+6x-10)
the distribute
8x^3-5x-1 -7x^2-6x+10
combine like terms
8x^3-11x+9-7x^2
use the communative property to reorder the equation
8x^3-7x^2-11x+9
Answer:
64
Step-by-step explanation:
95141 1404 393
Answer:
- arc BC: 8.55 cm
- chord BC: 8.03 cm
Step-by-step explanation:
The length of an arc that subtends central angle α will be ...
s = rα . . . . where α is in radians
The central angle BOC is twice the measure of angle QBC, so is 70°, or 7π/18 radians. So, the length of arc BC is ...
s = (7 cm)(7π/18) ≈ 8.55 cm . . . arc BC
__
For central angle α and radius r, the chord subtending the arc is ...
c = 2r·sin(α/2)
c = 2(7 cm)sin(35°) ≈ 8.03 cm . . . . chord AB
