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arlik [135]
3 years ago
9

2. Identify Chemical Changes (check all that apply)

Biology
1 answer:
I am Lyosha [343]3 years ago
4 0
Changes in the state of matter A, bubbling or fizzing B, and changes in volume F
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How does the cardiovascular system interact with the respiratory system?
jek_recluse [69]

Answer:

The circulatory and respiratory systems work together to pump blood and oxygen throughout the body. Air moves in and out of the lungs through the trachea, bronchi, and the bronchioles. Blood moves in and out of the lungs through the pulmonary arteries and veins that connect to the heart and thats how it works.

Explanation:

7 0
2 years ago
Read 2 more answers
A recessive gene located on the X chromosome is the cause of color blindness in affected individuals. Males are more likely to b
dangina [55]
The last one. Makes only have one X chromosome.
In turn if he has a daughter she's most likely to be color blind too.
6 0
2 years ago
What happens to the air around your vocal cords when you speak?
lidiya [134]
D. It expands and contrasts

Hope this helps!!
6 0
2 years ago
Which statement best describes the life cycle of plants such as ferns? Plants have a two-part life cycle, spending part of their
Gemiola [76]

The correct answer is that ferns have two part in their life cycle: Diploid phase and haploid phase

The life cycle of a fern has two parts: sporophyte stage and gametophyte stage. The gametophyte stage of ferns are haploid which releases gametes and the sporophyte stage are diploid that produces spores. This kind of life cycle is known as the "alternation of generation".




4 0
3 years ago
Read 2 more answers
Sickle-cell trait is caused by a single defective allele, but sickle-cell disease only occurs in individuals that are homozygous
Pavel [41]

Answer:

6,25%

Explanation:

Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:

Parents: Aa X Aa

Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)

Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:

A x A = 1/4 = 25%

A x a = 1/4 = 25%

a x A = 1/4 = 25%

a x a = 1/4 = 25%

The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:

1/4 × 1/4 = 1/16 = 0.0625 = 6.25%

It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.

6 0
3 years ago
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