The sequence of nucleotides in the template strand of DNA could code for the polypeptide sequence Phe-Ser-Gln is AAG, AGG, and GUU.
<h3>What are Nucleotides?</h3>
Nucleotides may be defined as a molecule that consists of a nitrogen-containing base, a phosphate group, and a pentose sugar.
The codons that codes for the given amino acids are as follows:
- Phe = UUC
- Ser = UCC
- Gln = CAA.
Therefore, The sequence of nucleotides in the template strand of DNA could code for the polypeptide sequence Phe-Ser-Gln is AAG, AGG, and GUU.
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Answer:
Noble Gases.
Explanation:
The reason why I say this is due to them having eight valence electrons, their outer energy levels are full.
Answer:
LysThrHis, LysHisThr, HisLysThr, HisThrLys, ThrLysHis, ThrHisLys
Explanation:
You easily combine the options for the tripeptide if you made a chart
Also you can calculate the posibilities with the factorial function in the calculatio (x!): 3*2*1 (you can multiplicate the number of amoniacids by the followed numbers until 1) = 6
It is rare for soft tissue to become a fossil because the soft parts can be eaten by other animals. Hope this helps!
One hypothesis that explains the result is : A) Two genes are involved with 12:3:1 epistasis, such that A_B_ and A_bb are black, aaB_ is brown,and aabb is green.
Explanation:
- This is a case of Dominant Epistasis.
- When two genes are involved and presence of dominant allele of one gene masks the effect of either allele of the second gene then the epistasis is termed as dominant epistasis.
- In the given case black :brown: green ratio is approximately equal to 12:3:1.
- Here presence of a dominant A allele that is responsible for the black colour masks the effect of either allele of B. Therefore A_B_ and A_bb produces black beetles
- Again , absence of dominant A allows B to express itself and Brown beetles are produced thus aaB_ is brown.
- When both the genes are present as recessive alleles, neither brown nor black colour is expressed and the beetles are green.Thus, aabb are green.