Answer:
1/36
Step-by-step explanation:
On the first throw, the probability of rolling any particular number, 1 through 6, is 1 out of 6. So the chance of rolling a 4 is 1/6.
On the second roll, your probability of rolling a 2 is 1/6.
The 'trick' is knwoing what to do with those two numbers.
Here's the rule: If events are dependent on one another, you multiply the probabilities.
Any time you see a scenario where X has to happen <u>and then </u>some other thing (X, Y, or whatever) has to happen, the events are dependent.
Probability of rolling a 4 <u>and then</u> rolling a 2 = 1/6 * 1/6 = 1/36
Hope this helps.
Answer:
3/8, 6/8, 5/8
Step-by-step explanation:
that is the right answer
Answer:
3
Step-by-step explanation:
The factor (x - 8) has 1 zero at x = 8
The factor (x + 3)² has a zero at x = - 3 of multiplicity 2
In total there are 3 zeros
The question is somehow incomplete but the answer is it in
the inferential stage of probability-based inference. It is in
complex networks of codependent variables is an lively theme in statistical
research, encouraged by such varied presentations as predicting, pedigree examination
and troubleshooting.
Let the profit at the first year be X
3x=114000
Solve for x by dividing each side by 3
3x/3=114000/3
X=38,000
So the profit was 38000
