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2 years ago

Please answer! Will give brainliest please and thank you

Mathematics

1 answer:

nydimaria [60]2 years ago

8 0

Answer:

119 square ft is the answer now give me brainliest

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I NEED HELPPPPP. SOMEONE ANSWER THISSSS

Inga [223]

Answer:y=415 x = 21.5

Step-by-step explanation:

We can see 4x-37 = 49

4x = 86

x = 21.5

4(21.5) -3 = 83

Then we can see what the other side is because they are equal

y/5 = 83

83 x 5 = 415

y=415

3 0

3 years ago

Read 2 more answers

The area of the right triangle shown is 24 square feet. Which equations can be used to find the lengths of the legs of the trian

Yuri [45]

Not sure, but the areas of a triangle is BH/2 so the dimensions should be 8 and 6 then 10.
8 x 6 = 48
48/2 = 24
Maybe that can help with the equation

4 0

3 years ago

Read 2 more answers

The concentration C (in mg/dl), of a certain antibiotic in a patient's bloodstream is given by C(t)=50 t /(t^2 + 25) where t is

marishachu [46]

Given that the concentration has been modeled by the formula:
C(t)=50t/(t^2+25)
where:
t is time in hours.
The concentration after 5 hours will be given by:
t= 5 hours
plugging the value in the equation we get:
C(5)=(50(5))/(5^2+25)
simplifying the above we get:
C(5)=250/(50)=5 mg/dl

Answer: 5 mg/dl

8 0

3 years ago

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

algol [13]

Find the critical points of $f(x,y)$ :

$\dfrac{\partial f}{\partial x}=-2x=0\implies x=0$

$\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12$

All three points lie within $D$ , and $f$ takes on values of

$\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}$

Now check for extrema on the boundary of $D$ . Convert to polar coordinates:

$f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t$

Find the critical points of $g(t)$ :

$\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0$

$\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2$

$\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi$

where $n$ is any integer. There are some redundant critical points, so we'll just consider $0\le t< 2\pi$ , which gives

$t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3$

which gives values of

$\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}$

So altogether, $f(x,y)$ has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0

3 years ago

Graph the function y=-2 then state the domain and range of the function

melomori [17]

Range is {-2}
Domain is (-infinity,infinity)

3 0

3 years ago