3 years ago

An estimated measurement was guessed of 10.4 mL and the actual measurement was 9.7 mL. What is the percent error?

Mathematics

2 answers:

kifflom [539]3 years ago

7 0

The answer to this question would have to be 13%

Softa [21]3 years ago

4 0

Answer:

7.22%

Step-by-step explanation:

Percent error is determined by dividing the difference between the guessed and the actual, divided by the actual, here you .7 divided by 9.7, which is .07216495, move the decimal two places to the right and round to the nearest hundredth and you get 7.22%

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finlep [7]

Answer:

$\boxed{B. \: 5 {x}^{6} + 5 {x}^{5} + 8 {x}^{2} - x + 2}$

Step-by-step explanation:

$= > (2 {x}^{6} + 8 {x}^{2} - x + 1) + (3 {x}^{6} + 5 {x}^{5} + 1) \\ \\ = > 2 {x}^{6} + 8 {x}^{2} - x + 1 + 3 {x}^{6} + 5 {x}^{5} + 1 \\ \\ = > 2 {x}^{6} + 3 {x}^{6} + 5 {x}^{5} + 8 {x}^{2} - x + 1 + 1 \\ \\ = > 5 {x}^{6} + 5 {x}^{5} + 8 {x}^{2} - x + 2$