Suppose y=0. That means
<span>x+z = 18 </span>
<span>x-z = 26/5 </span>
<span>x = 58/5 </span>
<span>z = 32/5 </span>
<span>So, the largest x can be is 58/5 </span>
<span>Now, suppose we toss in y. If we subtract y/2 from both x and z, then the difference between x and z is still 26/5, and the sum is </span>
<span>(x-y/2) + y + (z-y/2) = x+z = 18 </span>
<span>For example, if y = 4, </span>
<span>x = 48/5 </span>
<span>y = 20/5 </span>
<span>z = 22/5 </span>
<span>x-z is still 26/5, and the sum is still 18. </span>
Answer:
33
Step-by-step explanation:
Answer:
6 miles
Step-by-step explanation:
miles : minutes
1 : 10
x : 60
60/10=6
x must equal 6
Answer:
3(2*-1)^2
solved is: 12
Step-by-step explanation: