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Airida [17]
3 years ago
11

At a garage sale, Petra priced her scooter for $15.50. She ended up selling it for $10.75. Find the percent of decrease in the p

rice of the scooter. Round the percent to the nearest tenth if necessary.
Mathematics
2 answers:
dem82 [27]3 years ago
5 0

Answer:

percent decrease is 30%

Step-by-step explanation:

Step one:

given data

Cost of scooter= $15.50

selling price= $10.75

Step two:

%decrease = Cost price-selling price/cost price

%decrease = (15.5-10.75/15.5)*100

%decrease =( 4.75/15.75)*100

%decrease = 0.30*100

%decrease =30%

therefore the percent decrease is 30%

KIM [24]3 years ago
4 0

Answer:

The percent of decrease in the price of the scooter is 30.6%.

Step-by-step explanation:

In order to calculate the percent of decrease, you have to divide the difference between the two numbers by the original number and multiply the result for 100:

% decrease=((10.75-15.50)/15.50)*100

% decrease=-0.306*100

% decrease= -30.6%

According to this, the answer is that the percent of decrease in the price of the scooter is 30.6%.

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svlad2 [7]

Answer:

(a) There are outliers

(b) x and x >62

Step-by-step explanation:

Given

\sigma = 14.92

\bar x = 22.0

q_0 = -24

q_1 = 14.5

q_2 = 24.5

q_3 = 33.5

q_4 = 64

Solving (a): Check for outliers

This is calculated using:

Lower = Q_1 - (1.5 * IQR) --- lower bound of outlier

Upper = Q_3 +(1.5 * IQR) --- upper bound of outlier

Where

IQR = Q_3 - Q_1

So, we have:

IQR = 33.5 - 14.5

IQR = 19

The lower bound of outlier becomes

Lower = Q_1 - (1.5 * IQR)

Lower = 14.5 - (1.5 * 19)

Lower = 14.5 - 28.5

Lower = -14

The upper bound of outlier becomes

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Upper = 33.5 + 1.5 * 19

Upper = 33.5 + 28.5

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So, we have:

-14 \le x \le 62 --- the range without outlier

Given that:

q_0 = -24  --- This represents the lowest data

q_4 = 64   --- This represents the highest data

-24 and 64 are out of range of -14 \le x \le 62.

Hence, there are outliers

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The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

x and x >62

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2 years ago
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3y2+y3−5)+(4y2−4y+2y3+8)
jeka57 [31]

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Step-by-step explanation:

3y2+y3+−5+4y2+−4y+2y3+8

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