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julsineya [31]
3 years ago
10

What is the heat of reaction (AH) of the following? C(s) + O2 (g) --> CO2 (g)

Chemistry
1 answer:
zlopas [31]3 years ago
8 0

Answer:

C co2 2co enthalpy

2 Answers. Ernest Z. The standard enthalpy of formation of carbon monoxide is -99 kJ/mol.

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To answer this question, you will read two articles. First, read Article 1.
Zina [86]
Bro you really expect us to read that for just 5 points and we all be to lazy to read that
7 0
3 years ago
Read 2 more answers
Question 1: A substance that is soluble in two liquids and makes an emulsion last longer is called what?
Pavlova-9 [17]

<u>Answer:</u>

1. A substance that is soluble in two liquids and makes an emulsion last longer is called "Emulsifier".

2. The process that reduces the size of particles so emulsions will last longer is called "Homogenization".

<u>Explanation:</u>

Emulsifiers are additives which enable two liquids to mix around each other. Water and oil separate in a container, for an instance, but using an emulsifier can make the liquids blend along. It is widely used on various foods and beverages. Egg yolks and mustard are a few examples of emulsifiers.

Homogenization is the physical mechanism by which the fat molecules in milk are broken down because then they stay incorporated instead of segregated as cream. Majority of the milk sold in the United States is homogenized.

3 0
3 years ago
Which is a fossil fuel?<br> O A. Coal<br> O B. Biomass<br> O C. Geothermal<br> O D. Nuclear
creativ13 [48]

Answer:

coal

Explanation:

fossil fuels are formed by natural process.

3 0
3 years ago
The mass of an atom of element x is equivalent to the total mass of 7 hydrogen atoms.
Agata [3.3K]

Answer:

Nitrogen

Explanation:

7 0
3 years ago
A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 124.0 L and a pressur
amm1812

Answer:

She lost 50.88 moles

Explanation:

Step 1: Data given

The volume of the tank = 124.0 L

The initial pressure = 104.0 atm

The temperature = 24.0 °C = 297 K

The pressure drops to 94.0 atm

The temperature stays constant at 297 K

Step 2: Calculate the initial number of moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒with p = the initial pressure = 104.0 atm

⇒with V = the initial volume = 124.0 L

⇒with n = the initial number of moles = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature= 297 K

n = (104.0*124.0)/(0.08206*297)

n = 529.14 moles

Step 3: Calculate final number of moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒with p = the initial pressure = 94.0 atm

⇒with V = the initial volume = 124.0 L

⇒with n = the initial number of moles = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature= 297 K

n = (94.0*124.0)/(0.08206*297)

n = 478.26 moles

Step 4: Calculate the difference of moles

529.14 moles - 478.26 moles = 50.88 moles

She lost 50.88 moles

4 0
3 years ago
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