1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ivanzaharov [21]
2 years ago
15

Temperature and kinetic energy have a relationship.

Chemistry
2 answers:
liraira [26]2 years ago
4 0

Answer:

\boxed {\boxed {\sf Temperature=Average \ kinetic \ energy}}

Explanation:

Temperature is also known as the <em>average kinetic energy </em>in a substance.

If there is an absence of heat in a substance, the particles move slower and the kinetic energy decreases. The temperature will be lower, because there is less kinetic energy.

If heat is present or applied, the particles move more, so kinetic energy increases. The temperature will be higher, since there is more kinetic energy.

So, the relationship is: temperature is the measure of average kinetic energy.

Alex17521 [72]2 years ago
4 0

Answer:

<em><u>DIRECT </u></em>

Explanation:

You might be interested in
Is a theory testable, yes or no?
Paraphin [41]
Yes because a theory is based on results and the results are part of the experiment and it being tested. You have to test the experiment and get results so yes a theory is testable.
5 0
3 years ago
A 3.00-L flask is filled with gaseous ammonia, NH3. The gas pressure measured at 27.0 ∘C is 2.55 atm . Assuming ideal gas behavi
Whitepunk [10]

Answer : The mass of ammonia present in the flask in three significant figures are, 5.28 grams.

Solution :

Using ideal gas equation,

PV=nRT\\\\PV=\frac{w}{M}\times RT

where,

n = number of moles of gas

w = mass of ammonia gas  = ?

P = pressure of the ammonia gas = 2.55 atm

T = temperature of the ammonia gas = 27^oC=273+27=300K

M = molar mass of ammonia gas = 17 g/mole

R = gas constant = 0.0821 L.atm/mole.K

V = volume of ammonia gas = 3.00 L

Now put all the given values in the above equation, we get the mass of ammonia gas.

(2.55atm)\times (3.00L)=\frac{w}{17g/mole}\times (0.0821L.atm/mole.K)\times (300K)

w=5.28g

Therefore, the mass of ammonia present in the flask in three significant figures are, 5.28 grams.

8 0
3 years ago
24. Which Portuguese explorer sailed around Africa and across the Indian Ocean to reach India?
Sliva [168]

Answer:

Vasco de Gama

Explanation:

4 0
3 years ago
Read 2 more answers
Which two practices are examples of how people use sciense
Semenov [28]

Answer: A: Explaining natural events using facts and data AND B:Developing theories using many lines of evidence

Explanation: trust me.

6 0
2 years ago
If a ballon at 3.4 atm at 301k, what is the pressure when cooled to 212k
stepladder [879]

Answer:

2.39 atm

Explanation:

- Use Gay-Lussac's law

- P2 = P1T2/T1

- Fill in with our values

- Hope this helped! Please let me know if you need further explanation.

8 0
3 years ago
Other questions:
  • What is the term for the force exerted on an object by another object?
    5·1 answer
  • How many mL are in a cubic centimeter? 1,000 10,000 100,000 <br> none of the above
    7·2 answers
  • Boron has 5 protons. If another proton gets added to boron, what will happen?
    15·2 answers
  • Lead ions can be removed from solution by precipitation with sulfate ions. Suppose a solution contains lead(II) nitrate.Write a
    15·2 answers
  • How many boxes of B would be required to make 30 grams of C?
    10·1 answer
  • Question 4 (2 points)<br> CuO(s) + H2(g)<br> Cu(s) +<br> H2O(1)<br> Balance the equation
    14·1 answer
  • How many atoms are in carbon 12
    8·2 answers
  • ​If you needed a 1.5 x 1 0-4 M solution of a compound that has a molar mass of 760 g/mol, what would it concentration be in part
    6·1 answer
  • Determine the molecular formula of a compound having an empirical formula of CH and an experimental molar mass of 78 g/mol. Expl
    7·1 answer
  • Question 12 of 32
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!