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2 years ago

Temperature and kinetic energy have a relationship.

Chemistry

2 answers:

liraira [26]2 years ago

4 0

Answer:

$\boxed {\boxed {\sf Temperature=Average \ kinetic \ energy}}$

Explanation:

Temperature is also known as the average kinetic energy in a substance.

If there is an absence of heat in a substance, the particles move slower and the kinetic energy decreases. The temperature will be lower, because there is less kinetic energy.

If heat is present or applied, the particles move more, so kinetic energy increases. The temperature will be higher, since there is more kinetic energy.

So, the relationship is: temperature is the measure of average kinetic energy.

Alex17521 [72]2 years ago

4 0

Answer:

DIRECT

Explanation:

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In a step-down transformer, which side has more wire loops?

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3 years ago

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If equal volumes of 0.1 M HCl and 0.2 M TRIS (base form) are mixed together. The pKa of TRIS is 8.30. Which of the following sta

blondinia [14]

Answer:

option D is correct

D. This solution is a good buffer.

Explanation:

TRIS (HOCH $_{2}$ ) $_{3}$ CNH $_{2}$

if TRIS is react with HCL it will form salt

(HOCH $_{2}$ ) $_{3}$ CNH $_{2}$ + HCL ⇆ (HOCH $_{2}$ ) $_{3}$ NH $_{3}$ CL

Let the reference volume is 100

Mole of TRIS is = 100 × 0.2 = 20

Mole of HCL is = 100 × 0.1 = 10

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8.3 + log(10/10)

8.3

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3 years ago

For the reaction o(g) + o2(g) → o3(g) δh o = −107.2 kj/mol given that the bond enthalpy in o2(g) is 498.7 kj/mol, calculate the

Aneli [31]

The reaction;
O(g) +O2(g)→O3(g), ΔH = sum of bond enthalpy of reactants-sum of food enthalpy of products.
ΔH = ( bond enthalpy of O(g)+bond enthalpy of O2 (g) - bond enthalpy of O3(g)
-107.2 kJ/mol = O+487.7kJ/mol =O+487.7 kJ/mol +487.7kJ/mol =594.9 kJ/mol
Bond enthalpy (BE) of O3(g) is equals to 2× bond enthalpy of O3(g) because, O3(g) has two types of bonds from its lewis structure (0-0=0).
∴2BE of O3(g) = 594.9kJ/mol
Average bond enthalpy = 594.9kJ/mol/2
=297.45kJ/mol
∴ Averange bond enthalpy of O3(g) is 297.45kJ/mol.

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3 years ago

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3 years ago

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