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Makovka662 [10]
3 years ago
9

PLEASE HELP I NEED THE ANSWER ASAP

Mathematics
1 answer:
bixtya [17]3 years ago
8 0

Answer:

0.064

Step-by-step explanation:

(2/5) * (2/5) * (2/5)

= 0.064

Hope this is helpful!!! :)

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Semmy [17]
60/12 equal 5, so the answer would be that the walnuts fill <span>5 containers</span>
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What is the graph of 4x + 8y = 16?
Vinil7 [7]

Answer: Slope:  -1/2     y-intercept:  2

Step-by-step explanation:

Subtract 4 x from both sides of the equation. 8 y = 16 − 4 x Divide each term by 8 and simplify. Divide each term in 8 y = 16 − 4 x by 8 . 8 y 8 = 16 8 + − 4 x 8 Cancel the common factor of 8 . Tap for fewer steps... Cancel the common factor. 8 y 8 = 16 8 + − 4 x 8 Divide y by 1 . y = 16 8 + − 4 x 8. y=2−x2. The slope-intercept form is y = m x + b , where m is the slope and b is the y-intercept. y = m x + b Reorder 2 and − x 2 . y = − x 2 + 2. Rewrite in slope-intercept form. y = − 1 2 x + 2.Slope:−1/2  y-intercept:2

8 0
3 years ago
Patricia baked some cupcakes for sale. she put half of the cupcakes equally into 6 big boxes and the other half equally into sma
mojhsa [17]

Answer:

The answer is given below

Step-by-step explanation:

a)

Let us assume Patricia baked x number of cakes. She put half of the cupcakes (i.e x/2) equally into 6 big boxes.

6 big boxes contained \frac{x}{2} cakes, therefore 1 big box would contain \frac{x}{2}/6=\frac{x}{12} cakes.

Let us assume she put the other half into 14 small boxes, therefore each small box would contain \frac{x}{2}/14=\frac{x}{28} cakes.

There were 45 cupcakes in 3 big boxes and 8 small boxes altogether. That is:3(\frac{x}{12} )+8(\frac{x}{28})=45\\ 84x+96x=15120\\180x=15120\\x=84

Therefore Patricia baked 84 cup cakes

b)

She sold all the small boxes and collected $189, i.e she sold 14 small box for $189. Each small box = $189/14 = $13.5

6 0
4 years ago
Help!! I need help with this question
agasfer [191]

Answer:

the answer is going to be

C. X³+X²

3 0
4 years ago
Here are the endpoints of the segments BC, FG, and JK.<br> B, −67
yulyashka [42]

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}

F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}

JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill

4 0
2 years ago
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