Question

What is the value of i^n in if the remainder of n/4 is 2?

Answer 1

The value of ${i^n}$ is $\boxed{ - 1}$ if the remainder of $\dfrac{n}{4}$ is 2.

Further Explanation:

Given:

The remainder of $\dfrac{n}{4}$ is 2.

Explanation:

The sum of imaginary numbers and real numbers is known as the complex number.

The complex number can be expressed as follows,

$\boxed{z = a + ib}$

Here, a is the real part of the complex number and $\text{ib}$ is the imaginary part of the complex number.

$\sqrt{ - 1}$ can be denoted by i.

The value of ${i^2}$ is -1.

${i^2} = - 1$

The value ${i^3}$ can be obtained as follows,

$\begin{aligned}{i^3}&= {i^2} \times i\\&= - 1 \times i \\&= - i\\\end{aligned}$

The value ${i^4}$ can be obtained as follows,

$\begin{aligned}{i^4} &= {i^2} \times {i^2}\\&= - 1 \times - 1 \\&= 1\\\end{aligned}$

The value of ${i^n}$ is $\boxed{ - 1}$ if the remainder of $\dfrac{n}{4}$ is $2$.

Learn more:

1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Complex numbers

Keywords: value, $i^ n$, remainder, n/4, 2 quotient, divisor, complex number, imaginary number, real number, exponents, dividend, powers, -1, imaginary roots.

Answer 2

i² = -1

_____

i⁰ = 1

i¹ = i

i² = -1

i³ = -i

and then the pattern repeats