Answer with Step-by-step explanation:
Let k be the first even integer
then, next even integer will be k+2
and the next consecutive even integer will be k+4
Sum of three consecutive even integers was 4 times the first of those integers.
i.e. k+(k+2)+(k+4)=4k
3k+6=4k
6=4k-3k
i.e. k=6
Jared wrote and solved the equation:
k+ (k+1) + (k+2) = 4k
i.e. 3k+3=4k
i.e. 4k-3k=3
i.e. k=3
No, he didn't get the correct answer
(since, he wrote 3 consecutive integers as k,k+1 and k+2 instead of k,k+2 and k+4)