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MAXImum [283]
3 years ago
5

print out the last even number from an array of integers, if there is no even number, then print out a sentence indicating so.

Computers and Technology
1 answer:
den301095 [7]3 years ago
6 0

Answer:

See the sample algorithm below.

Explanation:

array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 22];

function last_even(arr) {

    for( i = arr.length-1; i >= 0; i--) {

         if (arr[i] % 2 == 0) {

              console.log(arr[i]);

              break;

         }

         else {

              console.log("There is no even number!");

         }

    }

}

last_even(array);

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Finish and test the following two functions append and merge in the skeleton file:
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Answer:

Explanation:

#include <iostream>

using namespace std;

int* append(int*,int,int*,int);

int* merge(int*,int,int*,int);

void print(int*,int);

int main()

{ int a[] = {11,33,55,77,99};

int b[] = {22,44,66,88};

print(a,5);

print(b,4);

int* c = append(a,5,b,4); // c points to the appended array=

print(c,9);

int* d = merge(a,5,b,4);

print(d,9);

}

void print(int* a, int n)

{ cout << "{" << a[0];

for (int i=1; i<n; i++)

cout << "," << a[i];

cout << "}\n";

}

int* append(int* a, int m, int* b, int n)

{

int * p= (int *)malloc(sizeof(int)*(m+n));

int i,index=0;

for(i=0;i<m;i++)

p[index++]=a[i];

for(i=0;i<n;i++)

p[index++]=b[i];

return p;

}

int* merge(int* a, int m, int* b, int n)

{

int i, j, k;

j = k = 0;

int *mergeRes = (int *)malloc(sizeof(int)*(m+n));

for (i = 0; i < m + n;) {

if (j < m && k < n) {

if (a[j] < b[k]) {

mergeRes[i] = a[j];

j++;

}

else {

mergeRes[i] = b[k];

k++;

}

i++;

}

// copying remaining elements from the b

else if (j == m) {

for (; i < m + n;) {

mergeRes[i] = b[k];

k++;

i++;

}

}

// copying remaining elements from the a

else {

for (; i < m + n;) {

mergeRes[i] = a[j];

j++;

i++;

}

}

}

return mergeRes;

}

4 0
4 years ago
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