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tekilochka [14]
3 years ago
15

There are parallels between the trust models in Kerberos and Public Key Infrastructure (PKI). When we compare them side by side,

Kerberos tickets correspond most closely to which of the following?
a. private-key certificates.
b. private keys.
c. public-key certificates.
d. public keys.
Computers and Technology
1 answer:
Ivanshal [37]3 years ago
6 0

Answer:

<u>c. public-key certificates.</u>

Explanation:

It is important to<em> note</em> that in Kerberos infrastructure, <em>tickets </em>are issued by a third party as part of the authentication process.

This authentication process corresponds most closely to that of the Public Key certificates Infrastructure since it is a third party that issues out tickets to authenticate both parties engaged in the communication over a network.

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A network technician is someone who maintains, and repairs computer systems and they also set up several Internet connections, and networks.

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4 years ago
Which devices are most likely to communicate with the internet? Select 3 options.
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5 0
3 years ago
Write a program that takes as input a number of kilometers and prints the corresponding number of nautical miles. Use the follow
Dmitrij [34]
<h2>Answer:</h2>

import java.util.Scanner;

public class NauticalMiles{

   public static void main (String [ ] args){

      Scanner input = new Scanner(System.in);

      System.out.println("Please enter the number of kilometers");

      double km = input.nextDouble();

      double nm = 0.54 * km;

      System.out.println("The corresponding number of nautical miles is "  + nm);

    }

}

<h2>Explanation:</h2><h2></h2>

<em>1 => Pre-code analysis</em>

According to the question,

(a) <em>A nautical mile (nm) is 1 minute of an arc.</em>

=> 1 nm = 1 minute of an arc

(b)<em>There are 90 degrees, each containing 60 minutes of arc, between the North pole and the equator.</em>

=> Each of the degrees in 90 degrees has 60 minutes of arc

=> 1^{0} = 60 minutes of arc

=> 90^{0} = 90 x 60 minutes of arc

=> 90^{0} = 5400 minutes of arc

(c) <em>A kilometer (km) represents 1/10,000 of the distance between the North pole and the equator. </em>

=> A kilometer = (1 / 10000) x distance between the North pole and equator.

Remember that the distance between the North pole and the equator as shown in (b) above is 90 degrees which is equal to 5400 minutes of arc.

=> 1 km = (1 / 10000) x 5400 minutes of arc

=> 1 km = (1 / 10000) x 5400 x 1 minute of arc

As shown in (a) above, 1 minute of arc is 1 nautical mile(nm).

=> 1 km = (1 / 10000) x 5400 x 1 nm

<em>=> 1 km = 0.54 nm.</em>

=========================================================

<em>2 => The code analysis</em>

The code has been written in Java.

The following is the line-by-line explanation of the code written as comments.

// Import the scanner class to allow for user's inputs

import java.util.Scanner;

// Declare the main class to hold and run the application

public class NauticalMiles {

   // Write the main method where execution will begin

   public static void main (String [ ] args) {

      // Create an object <em>input </em>of the Scanner class  

      Scanner input = new Scanner(System.in);

     

      // Prompt the user to enter the number of kilometers

      System.out.println("Please enter the number of kilometers");

      // Store the user's input in a double variable called <em>km</em>

      double km = input.nextDouble();

      // Convert the input to nautical miles using the formula from the

      // pre-code analysis above. i.e 1km = 0.54nm.

      // Store the result in a double variable called <em>nm</em>

      double nm = 0.54 * km;

      // Print out the result (the nautical mile)

      System.out.println("The corresponding number of nautical miles is "  + nm);

    }       // End of main method

}            // End of class declaration

=========================================================

<em>3 => Sample output</em>

<em></em>

> Please enter the number of kilometers

>> <em>45</em>

> The corresponding number of nautical miles is 24.3

8 0
4 years ago
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