Answer:
Sequence of popped values: h,s,f.
State of stack (from top to bottom): m, d
Explanation:
Assuming that stack is initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:
push(d) -> enters d to the Stack
Stack:
d ->top
push(h) -> enters h to the Stack
Stack:
h ->top
d ->bottom
pop() -> removes h from the Stack:
Stack:
d ->top
p: Suppose p contains popped values so first popped value entered to p is h
p = h
push(f) -> enters f to the Stack
Stack:
f ->top
d ->bottom
push(s) -> enters s to the Stack
Stack:
s ->top
f
d ->bottom
pop() -> removes s from the Stack:
Stack:
f ->top
d -> bottom
p = h, s
pop() -> removes f from the Stack:
Stack:
d ->top
p = h, s, f
push(m) -> enters m to the Stack:
Stack:
m ->top
d ->bottom
So looking at p the sequence of popped values is:
h, s, f
the final state of the stack:
m, d
end that is the top of the stack:
m
I’m 98% sure that it is B because customer service would be provided to people who buy from the company and need help
Answer:
<em>The program is written in python and it doesn't make use of any comment; </em>
<em>(See explanation section for line by line explanation)</em>
def getN(num):
fact = 1
for i in range(1, 1 + num):
fact = fact * i
print("Factorial: ",fact)
num = int(input("Number: "))
if num < 0:
print("Invalid")
else:
getN(num)
Explanation:
The function getNum is defined here
def getN(num):
Initialize the result of the factorial to 1
fact = 1
Get an iteration from 1 to the user input number
for i in range(1, 1 + num):
Multiply each number that makes the iteration
fact = fact * i
Print result
print("Factorial: ",fact)
Ths line prompts user to input number
num = int(input("Number: "))
This line checks if user input is less than 0; If yes, the program prints "Invalid"
if num < 0:
print("Invalid")
If otherwise, the program calls the getN function
else:
getN(num)
Answer:
Answered below
Explanation:
Scanner n = new Scanner(System.in);
System.out.print("Enter number of guests: ");
int numOfGuests = n.nextline();
double pricePerGuest = 35.0;
double totalAmount = numOfGuests * pricePerGuest;
String event = " ";
if ( numOfGuests >= 50){
event = "Large event";
}else{
event = "small event";
}
System.out.print(numOfGuests);
System.out.println(pricePerGuest);
System.out.println( totalAmount);
System.out.println(event);
