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Tresset [83]
3 years ago
15

What is the m∠2 if m∠4 = 81° and m∠3 = 40°? a. 40° b. 59° c. 41° d. 60°

Mathematics
2 answers:
velikii [3]3 years ago
8 0

Answer:

C. 41

Step-by-step explanation:

180 - 81 = 99

99+40 = 139

180 -139 = 41

Aleks04 [339]3 years ago
5 0

Answer: B. 59 degrees

You need to add Angle 4 which is 81 to Angle 3 which is 40

81+40=121 and then we will subtract it from 180

180-121=59 degrees

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riadik2000 [5.3K]

Let the two consecutive even integers be 'x' and 'x+2'.

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Since, twice the lesser of two integers is 4 less than two times the greater integer.

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2x = 2x +4 -4

Therefore, x =0

Hence, x+ 2 = 2

Therefore, 0 and 2 are the required consecutive even integers.

3 0
3 years ago
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malfutka [58]
I believe it's the third one
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3 years ago
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Describe the symmetry of these functions
Oduvanchick [21]
If it was line symmetry it would need to repeat the same shape twice, which the first follows but the second doesn’t.
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the answer is C
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3 years ago
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How many grams of 0.5% hydrocortisone cream must be mixed with 180 g of 2.5 % cream to make a 1 % w/w hydrocortisone cream? HINT
Sophie [7]

Answer:

We need 540 grams of 0.5% hydrocortisone cream

Step-by-step explanation:

Lets call x the amount of grams needed. This means that the combined cream will have 180+x grams. We want x such that

x * 0.005 + 180*0.025 = (180+x)*0.01

Hence

0.005x + 4.5 = 1,8+0.01x

Lets put the x in the same side and take common factor

4.5-1.8 = 0.01x-0.005x

2.7 = (0.01-0.005)x = 0.005x

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3 0
3 years ago
How many different 11-letter arrangements can be made using the letters in the word Firecracker?
zhenek [66]

Answer:

Total number of arrangements = 1,663,200

Step-by-step explanation:

Given:

11 - letter

FIRECRACKER

F = 1

I = 1

R = 3

E = 2

C = 2

A =1

K = 1

Find:

Total number of arrangements = ?

Computation:

Note: Repeated letter will be avoid.

Number\ of\  arrangements = \frac{!11}{!3 \times !2 \times !2}\\\\Number\ of\  arrangements = \frac{!11}{!3 \times !2 \times !2} \\\\Number\ of\  arrangements = \frac{11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3}{3 \times 2 \times 2 } \\\\Number\ of\  arrangements = 1,663,200

Total number of arrangements = 1,663,200

6 0
4 years ago
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