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stellarik [79]
3 years ago
5

Hich values are solutions to the inequality?

Mathematics
2 answers:
Troyanec [42]3 years ago
7 0

2r\leq3r-8\\0\leq r-8\\8\leq r\\r\geq8

So, in the list of numbers, 8 and 9 are solutions

Ede4ka [16]3 years ago
7 0

Answer:

8 and 9

Step-by-step explanation:

1. subtract 3r from both sides to get -1r≤-8

2. divide both sides by -1 to get r by  itself r=8

3. any number greater than 8 will be a true statement

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N/8 -3 = 16. <br> A student got n=5 is the student correct yes or no<br> 50 points I guess
amid [387]

thank you for the points

5 0
2 years ago
Sonia uses $12.50 to buy a new journal. She has $34.25 left in her savings account. How much money did Sonia have before she bou
GalinKa [24]
So all you have to do to find out how much she had before is add up both value 12.50+34.25=   46.75$ (answer)

because y-12.50=34.25 so you would have to had the 12.5 to the other side to find the value of Y
3 0
3 years ago
an airplane flies from city a to city b, which is 100 kilometers north and 150 kilometers west of city a. how far does the plane
frozen [14]

Answer:250 kilometers

Step-by-step explanation:

so it travels 100 kilometers north and another 150 kilometers north so 100+150 is 250 kilometers

3 0
1 year ago
Express the terms of the following geometric sequence recursively.
BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2

Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

Where;

a₁ = The first term

r = The common ratio

n = The number of terms

The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
Clark put 3000 in an account that compound 5% interest twice a year. if she left the money in for a year how much should have​
AlexFokin [52]

Step-by-step explanation:

A = P (1 + r/n) (nt)

   A = the future value of the investment/loan, including interest

   P = the principal investment amount (the initial deposit or loan      amount)

   r = the annual interest rate (decimal)

   n = the number of times that interest is compounded per unit t

   t = the time the money is invested or borrowed for

p = 3000

r = 5%/100 = .05 (has to be in decimal format)

n = 2

t = 1

A = 3000(1 + .05/2)⁽²ˣ¹⁾  note (make sure you use ^ (power of) for the 2x1)

use PEMDAS to work out problem

P arenthesis

E exponents

M ultiplication

D ivision

A ddition

S ubtraction

A = 3000(1 + .05/2)⁽²ˣ¹⁾

a = 3000(1 + .025)^²

a = 3000(1.025)^2

a = 3000 x 1.050625

a = 3151.875

she would have $3,151.88

4 0
3 years ago
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