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ehidna [41]
3 years ago
9

write the formula to calculate area of quadrilateral when Co ordinates are given​ can you answer it please...

Mathematics
2 answers:
Alexxx [7]3 years ago
3 0

If four coordinates are given then:-

  • Find length of the sides using distance formula

\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

  • Now break down into two triangles .
  • Use herons formula and find areas of the triangles .add them and get the area
dsp733 years ago
3 0

Answer:

Area of Quadrilateral Using Coordinates

Subtract (2) from (1) and multiply the difference by 1/2 to get area of the quadrilateral ABCD.

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Answer:

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What is the approximate value of the square root of 8 to the nearest tenth?
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5. What is the solution of |3x-3|_&lt;18?
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WORK...
|3x-3| \leq 18&#10;

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8 0
3 years ago
Plz plz help me so i can get a good grade
Levart [38]

Area of the figure = 806.5 in²

Solution:

Length of the rectangle = 16 in

Breadth of the rectangle = 9 in

Area of the rectangle = length × breadth

                                    = 16 × 9

Area of the rectangle = 144 in²

Base of the triangle = 31 in

Height of the triangle = 20 in

Area of the triangle = \frac{1}{2}bh

                                 $=\frac{1}{2}\times 31\times 20

Area of the triangle = 310 in²

Parallel sides of the trapezium = 16 in and 31 in

Height of the trapezium = 35 – 20 = 15 in

Area of the trapezium = \frac{1}{2}\times \text{Sum of the parallel sides}\times \text{Height}

                                     $=\frac{1}{2}\times {(16+31)}\times{15}

                                     $=\frac{1}{2}\times {47}\times{15}

Area of the trapezium = 352.5 in²

Area of the figure = Area of rectangle + Area of triangle + Area of trapezium

                              = 144 in² + 310 in² + 352.5 in²

Area of the figure = 806.5 in²

8 0
3 years ago
Solve 0 Divided by 0
galina1969 [7]
It would come out as an error because you cant divide nothing by nothing. There is nothing there to divide
3 0
3 years ago
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