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belka [17]
3 years ago
13

If it takes Matthew an hour to get to his friend’s house, and two hours if he drives 25 mph slower, how far away does Matthew’s

friend live?
Mathematics
2 answers:
pishuonlain [190]3 years ago
6 0

Answer:

he lives 50 miles away

Step-by-step explanation:

if he was driving 50 mph the first time he would take an hour.

the second time he goes half the speed so it takes double the time. 50/2=25

vodka [1.7K]3 years ago
3 0

50 miles hope this helped :)

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You are trying to estimate the average amount a family spends on food during a year. In the past the standard deviation of the a
svetoff [14.1K]

Answer:

n=(\frac{2.58(1000)}{50})^2 =2662.56 \approx 2663

So the answer for this case would be n=2663 rounded up to the nearest integer

Step-by-step explanation:

We have the following info:

ME = 50 margin of error desired

\sigma = 1000 the standard deviation for this case

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =50 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance is \alpha=0.01. And for this case would be z_{\alpha/2}=2.58, replacing into formula (b) we got:

n=(\frac{2.58(1000)}{50})^2 =2662.56 \approx 2663

So the answer for this case would be n=2663 rounded up to the nearest integer

5 0
3 years ago
Which expression is equal to 20.92 ÷ 6.8?
vesna_86 [32]

Answer:

D

Step-by-step explanation:

They both equal 3.08

The decimal is moved one to the right on both so the answer will be the same

4 0
3 years ago
PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
aniked [119]

Answer:

5:9

6:5

7:-6

Step-by-step explanation:

7 0
3 years ago
Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

i)For every x there is y such that

                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

                                        2(2-y)-y=1\\4-2y-y=1\\4-3y=1\\-3y=1-4\\-3y=-3\\y=1

Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

5 0
3 years ago
Ok so I need help thank you
Liula [17]

Answer:

2.56

Step-by-step explanation:

I'm pretty sure, I'm sorry if its wrong

5 0
3 years ago
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